Haloalkanes and Haloarenes | ALL CONCEPTS 🧪 | NEET 2026 | Riyaz Anna | Iruthi Sutru 2.0

Oh hello, hi, hi, hi, hi, hi, hi, good evening everyone. Sir, good evening, good evening, good evening, good evening, good evening. Okay, so how many people have gotten clarity in SN1, SN2, E1, E2 so far? You are here, who has never got clarity in SN1, SN2, E1, E2 based questions? Yes. So, that's what we are going to tackle today. The important thing here is that today I have brought some public questions. Okay, so just a minute, let me just open my laptop. I'll open my laptop. Vandi veera nanadi, unakkuthaana nanadi. Okay, right. We are going to see up to I. Not I, J. We are going to see up to J. We are going to see up to I, J. Not I, I mistakenly said I. Forgive me. Not up to I, let's see up to J. Why should we see up to I? No need of I. Okay, okay. I think many people haven't liked it yet. Everyone who hasn't liked, please like. Yes, everyone who is watching without liking, please like first. Okay? Have you liked it? I'll just open our train. We have some trains. We have good, good questions. So, I have come with the thought that we should not waste anything today. So, without wasting, we are all going to solve them like good students. Okay, yes. Okay, so it's opened. After this, we are going to hit it hard. Okay. So, let's see who all are here in today's session. Monish is there. RK, Puthithanya, Amma, no Amma, no chance Amma. These guys have already leaked the test paper. So, I won't give my precious lecture notes. Lakshika is here. Then Jenita, Durga, then Star Padi is here. Okay, many people are here. Nivetha, Prajin, then Phula is here. Nithishan, Rasika, Saravanan, Kavya, Ranjith, Dakshaya. Okay, okay, okay, okay, okay. So, okay. She has arrived. She, hi dear. Oh my god. Hey, don't pay attention to her. Nobody pay attention to that "hi dear" in the middle. Let her say "hi dear, bye dear" and leave. Okay, just ignore that. Dexter Talk, hi. Okay, so Sabina. Sabina? Is this name for looking at the head? Sabina? Okay. If anyone is still not there for the test series and mentorship, okay? We won't care at all. Then you will say, okay, okay, okay. We shouldn't say things so plainly. Okay, otherwise, it will become embarrassing outside. So, if you come here, if anyone hasn't joined the final round yet, please join. We are mostly thinking of increasing the price a bit. So, in case anyone hasn't joined yet, the price will increase. After that, I don't know anything. But have you increased the price? What is it? So, don't message me. That's all I will say. So, those who haven't joined the final round yet, please join. Next, the printed series. Yes, many of you who said you want it, please buy it as soon as possible. Everyone who bought yesterday, the day before yesterday, yesterday, has been dispatched. Most probably, you will be getting that in two or three days. Within two or three days, yes, the printed series will reach your hands. Okay? The printed series, for everyone, as soon as possible. Similarly, why is there a promo code, Diana? What is this, Anna? You are revealing my company secrets like this. You shouldn't reveal everything about giving promo codes. If you see, seriously, many places have started launching courses now. You come, I will make you finish this in 40 days. I will make you finish that in 40 days. Hey, you have to finish studying in this one month. Next month, you have to revise. What is this? Many people are launching courses here for no reason. New, new, I don't understand what this is. Okay, so yes, EMS Delhi in seven days? Okay, so if anyone here wants to buy this, please buy it directly from the website. Okay, so hello, alkyl halides. Hello, alkyl halides is a chapter where, in this chapter, have you seen drawing graphs? Have you seen? Have you seen? Have you seen drawing graphs? In this lesson, I will draw graphs. Come, come. I will draw graphs for you. Come, everyone. We will draw graphs in this lesson. Come, we will do everything in this lesson. We will do it. This lesson, we will do it. Pandya, sister. Okay, okay. So, come here. So, let's start. I will teach you a classification first. In this classification, if you look at the NEET 2022 paper, a question was asked from this classification. Allylic, what is the allylic position? A question came. Okay? What came? What came? A question based on the allylic position came. If you take all the previous year papers in organic chemistry, okay? If you take all the previous year papers, you can see one question. Either it will be based on hybridization, or it will be based on terms like these technical terms, where we give a name to a certain position. So, they asked in 2022. This year again, vinyl halide, or allylic, or geminal, vicinal, some question is likely to come. Okay? Okay? I'll say it again. I'll say it again and again. If you have kept your notes here, here, like this, turn your notes over like this, saying "the full moon will become the face." Okay? Just turn the notes over. Okay? Turn the notes over. The notes will definitely not be enough. Okay? So, have all of you turned your notes over? Turn them over. Write the heading "Classification." Classification. Yes, classification of halogen derivatives. Halogen, halogen derivatives. Okay. Shall I tell you another good news? How many of you want another good news? How many of you want another good news? How many of you want another good news? What do you think the good news will be? All of you, brother, hey, don't just keep saying "brother, brother." Hey, why would I get married? Actually, tomorrow, tomorrow, electrostatics. Okay, electrostatics. I'm planning to take it from the afternoon. In case electrostatics is finished, I will take electrostatic potential in the evening. And the next day, Sunday, capacitance. If capacitance is finished quickly, we will go to circuit analysis. Okay? Okay? Next, in the next few days, I am going to lock around six questions in physics for you. I'm saying six, even less. I can say six to seven to eight questions. Okay? Yes, you will be getting locked around seven to eight questions from these chapters because they ask around two questions from electrostatics, electric field. They ask around four questions from capacitance, electrostatic potential. So, apart from that, they ask around three questions from circuit analysis. So, if you are lucky, that seven might even increase to ten sometimes. Okay? So, in the next two days, in the next few days, we are going to finish all of this. Capacitance, circuit analysis, electrostatic potential, electrostatics. Okay, everything. Yes, tomorrow, four days. Haven't the gravitation notes been uploaded? I will tell them to upload, please wait. Okay, so here, tomorrow, most likely, I will start in the afternoon. But on Sunday, I don't know if I will start in the afternoon. On Sunday, because I have some work. I told you I have to give a surprise to two people. I mean, if there is any student from Chennai who is buying, I said you will get a surprise. I have arranged for that surprise on Sunday. That's why. Okay, I am a bit busy. Yes. So, if you come here, how are we going to divide this classification? Yes, we are going to divide it into three ways. Yes, we are going to divide it into three ways. Three ways. What are these three ways? Look here. First, on the basis of the number of halogen atoms. Okay? On the basis of the number of halogen atoms. On the basis of the number of bonds. Surprise me. If possible, I will try. Okay? On the basis of the basis of the number of halogen atoms. Number of halogen, halogen atoms. Okay? Number of halogen atoms. Based on how many there are, we are going to do the first classification. Second classification. Surely, many of you would have already studied this topic. You tell me. What is the second one? What is your second classification? Tell me first. Tell me first. What is your second classification? Based on the number of halogen atoms, we divided one classification. What is the next classification? Based on your hybridization. So, a total of two hybridizations. If one atom is attached here, think with common sense. I'm asking something with common sense. A halogen is attached here. This halogen is attached here. Then this carbon must have a double bond on one side. Or, it must be on a single bond on three sides. So, we can give a classification based on sp3. Then, can we give a classification based on sp2? Yes, can we give it or not? We can definitely give it, right? So, based on sp3 and sp, sp2. Lokheshwaran, hi. Hi, hi, hi, hi, hi. Okay. So, here, there will be two classifications. One is attached to your sp3 atom. Okay? Halogen. Okay? Next, when you come to the last classification, what is your last classification? I'll tell you. How many of you usually get confused between allylic and vinylic? How many of you usually get confused in the position of allylic and vinylic? Many people attend by making mistakes. Because questions are asked in many places, but still, people used to make mistakes in this question. Okay? If, if halogen, halogen connected to, connected to sp2 atom. Okay? sp2 atom. So, a total of three classifications. If you think there are only these three classifications, no. Under these, three more will come. That's why I told you to turn the page. Okay? Under these, three more will come. So, please, don't tell me "Anna, Anna, the page is not enough." Okay? So, come here. Oscillation part 2? It's in the app. Go and see. Okay. So, under this, one, two, three. Okay? One, two, three. Is there a math class for JEE students? If any of our boys who wrote JEE and went to NIT, IIT, want to teach, please contact us. We can start for JEE too. Definitely. It's not wrong to teach four people. Okay? While studying in college, do this good deed. Okay? I'm not telling you to teach for free. I will pay you a salary. Okay? You teach for free on YouTube. Okay? There are a lot of people getting scammed by some so-called orange candies in the name of JEE. We need to bring that out a bit. That's why I'm saying. So, come here. First, will the notes PDF not be available? PDF will be available, but only in our app. My notes are very precious, so I won't give them. So, first, look here. How many halogens can you attach? A carbon has four bonds. In those four bonds, you cannot think of kicking out the first wife and sitting in her place. First wife is constant. In the remaining three places, can you attach a halogen in one place or not? Yes, yes, you can definitely attach it. The last case will be there. In that also, you can kick out the first wife and sit in that place. Okay? So, you can divide and take it as four, four, four. Okay? You can divide and take it. So, a total of one, mono halogen derivative, another, dihalogen derivative, another, polyhalogen, trihalogen, or tetrahalogen derivative. Okay? So, how many are there in total? Okay? How many are there? How many are there? One, mono halogen. One is mono halogen. In mono halogen, how many will be there? It's in the name. Look here. Just one halogen will be attached. Look here, CH2X. What is your CH3 enemy? If only one atom is attached, your halogen, then what is it? What is your, your mono halogen derivatives? Next, dihalogen derivatives. Dihalogen, halogen derivatives. Okay? Yes, dihalogen. What will come here? Just, yes, taking something, we can attack X here, attack X here. How many of you will come under dihalogen? Okay? So, we can write it as CH2X2. Or, even this, CH2, here one X, if you put one X here, this also comes under your dihalogen. Okay? Okay? Okay? Okay? So, if you want, you can write another example here. Write as many examples as you want. Even if there is one X here, it also comes under that. Okay? You also come under dihalogen. So, sorry. Next, when you come to polyhalogen derivative. Okay, poly, poly halogen, poly halogen. In poly halogen, you have many. Okay? A lot. If you have bought the final round, there will be an option called final round in the app. Okay. After this, we have to be a bit silent. Otherwise, we will get some violent message. Okay. So, come here. Here, yes, here you have one X, one X, and then one X. Okay? So, a total of how many X's you can put. It's up to you. So, here, CH2, here CH, here CH2. Okay? So, here one X, here one X, here one X. Three, three. In this, CCl4, carbon tetrachloride, right? This is four. This is a separate thing. Okay, okay, okay, madam. Okay, madam. You are watching. Okay, madam. Okay, okay. Okay? So, this is your special example. Okay? Special, special example. This is for you. So, next, when you come, tell me if everyone has understood so far. We can move on. Yes, if everyone has understood so far, tell me. Shall we move on to the next one? Here, hey, what is this? You are all teasing me. I am watching. I am not ashamed. Okay, okay. Okay, next, when you come, we have a total of three, three classifications here. Okay? Yes, three, three, three classifications we have here. Okay? Three, three, three classifications we have here. What are these three classifications? Hey, what is this? You are all making me angry by throwing tomatoes. Please pay attention. Okay? Okay, okay, okay. Plus. Okay, okay, okay, okay. Enough, enough, enough. Everyone, everyone, everyone, please study. Okay? Okay, okay. Come, come, study, study, please study. Yes. So, good kids should study. Okay? Okay? Now, now, now, listen. Thank you, thank you, thank you. Your course is 9 riyals? 9 riyals? Yes, it's around 200. Yes, it's 9 riyals. Okay, so, here, you have a total of three classifications here. One is alkyl halide. What is alkyl? You tell me what alkyl means. Yes, what do you mean by alkyl? Generally, we know what alkyl means. If it's attached to a normal methyl group, yes, that is your alkyl halide. Yes, alkyl halide. Okay? The example for this alkyl halide is very simple. Again, we will have three classifications within this. So, that's your problem. Write it wherever you are writing in your notes. Okay? Okay? So, what is this here? Again, three will come. What are these three? Primary alkyl halide, secondary alkyl halide, and tertiary alkyl halide. So, in primary alkyl halide, look here. Okay? Here, CH2X. Look here, R, CH2. Okay? Here, CH, here X. What is this, the one at the end? R, CH, here R, here R. This has X. So, a total of three here, so it's tertiary. So, this is primary, X. This is secondary, X. Okay? This is your tertiary X. This is a very dumb concept that everyone definitely knows. Okay? What is the next concept? That's where. What is this? The next concept is our two more important concepts. The main thing here is your allylic halide. Allylic halide. I'll say it again. Allylic halide. Look here. I'll tell you how to differentiate. I've written everything correctly. Okay, okay, done. CH3 in secondary? Where, madam? Is it correct? It's correct. Okay? Yes. So, come here. Allylic. Where? Oh, above. BH3. Something will be missed here and there. That's human nature. Allylic halide. Okay? Allylic halide. Look here. Do you see two lines for everyone? Why do you see these two lines? Okay? Do you see these two lines? So, allylic means what? Next to the double bond, the adjacent carbon is what? Allylic position. What is allylic position? Is there anyone attached to the carbon adjacent to this double bond? But I'll say it again. NEET 2022, 2023, I don't remember correctly. In one of those papers, I am 100% sure, a question was asked based on allylic. It's still there. Take it and see. It will be from this chapter. Okay? So, take a look once. Because there was a question based on allylic. Okay? Okay? Here, CH. Where is your CH2 double bond, CH? There will be a carbon next to it. Remember one more thing. When the word allylic comes, is that atom attached to an sp3 hybridized atom or an sp2? Why sp3, sp2? Not 2024, not 2023, it was in 22 or 2. I definitely don't remember. Yes, allylic is always sp. Look here. What is the hybridization of this atom? It's sp3. So, it's definitely attached to sp3. That's true. Okay, look here. Now I'm drawing something. There's a double bond here. There's X here. Is this allylic or not? Tell me. Is this allylic or not? Of course, it's an allylic group because look, the double bond is here. The adjacent carbon is here. I've attached it to this one. Okay? Or, suppose I attached it here. What is it? Is it allylic or not? If I attach it correctly here, in red color, is it allylic or not? This is also allylic. Okay? So, you can attach it on either side, but it is an allylic. Okay? So, allylic. Definitely, next, another common mistake people do is that benzyl. What is it? Benzoyl. Look here, I'll say it again. Benzyl. So, they will give benzyl. Even if they give "zyl," many people will think of attaching it directly to benzene. Attaching directly to benzene is not benzyl. Okay? What is benzyl? Only when it's attached to a carbon attached to benzene is it benzyl. How many of you have already made this mistake? I definitely know that 100% many people, when solving questions, if benzyl was given, you would have solved it by assuming it was directly attached. So, you shouldn't make that mistake here. So, what will come next? Your benzylic halide. Okay? Benzylic halide. What is this? Look here. If you can't remember it, remember it by hybridization. Allylic, benzylic, all come under sp3 hybridization. So, it's definitely impossible for that atom to be directly attached. If it's directly attached, it will go to sp2. Okay? So, come here. Benzylic. Benzylic halide. Okay? Benzylic halide. Okay? So, in benzylic halide, look here. There will be an atom next to your benzene ring. Next to that atom, next to that atom. Okay? Here, look, next to it. CH2. Your X will be attached here. Okay? Or, if it's not like this, it can be either like this. Here, your carbon. There can be an R group on this side and an R group on this side. It can be attached to this. Either it can be like this. But the atom to which your X is attached should be an sp3 hybridized atom. So, if everyone has understood without doubt so far, tell me. We can move on. If everyone has understood without doubt so far, can we move on to the next one? Yes. So, next, when you come, regarding sp2, there are only two matters here. Okay? There are only two classifications for sp2. Who are those two classifications? Someone tell me. Come on. You would have already studied. Tell me. There are two classifications here. What are the two classifications out there? Yes. One is aryl, and the other is vinyl. In aryl, it might be mentioned as phenyl in many places. Okay? It might be mentioned as phenyl. So, aryl is the most correct name. Okay? Aryl halide. Aryl halide. Okay? Aryl halide. Another is vinylic halide. Vinylic halide. Okay? So, geminal and vicinal. I already taught both of them. How many of you remember? In which chapter did I teach you geminal and vicinal? In which chapter did I teach you geminal and vicinal? We already studied geminal and vicinal. Where did we study? Do you all remember studying it in hydrocarbons? So, geminal and vicinal will also come here. But I'm not going to teach that here. Because you have already studied it. The highlight here is that you would have already studied all its preparations. That's the highlight here. So, I'll teach that too. Come here. So, see here. Here, your benzene ring. Directly, yes, directly, if your X is attached here. Sorry, cause. Thank you, madam. Thank you, thank you, thank you. Look here. If it's directly attached, it's your aryl halide. Vinyl means, look here. A little while ago, I said, if this X is not attached here, but directly attached to this double-bonded carbon, what is it? Tell me, tell me, tell me. That's vinyl. Okay? So, if it's attached directly, that's your vinyl. So, look here, C double bond C. Here, your X will be attached. Okay? Or, if your double bond is like this, your X will be directly attached to it. Okay? So, if it's like this, it's your phenyl. So, till now, classification done. If no one has any doubts, tell me. We can move on. Yes. Look here. Always, something I teach. If you think with common sense again, with common sense, you will think that your alkene, alkane, etc., what type of reaction they show depends on their nature of the bond. Generally, were alkanes polar or non-polar? Were alkanes non-polar or polar? Nature of the CX bond. Okay? Okay. So, here, here, you obviously know that you obviously know that something. Here, a carbon is going to be attached to an X. Hydrogens are going to be attached to it. Here, this X, this X can neither be fluorine, chlorine, bromine, or iodine. Correct? Here, the electronegativity of this carbon is around 2.51, according to the Pauling scale. Okay? Pauling, Pauling, Pauling scale. Okay? Now, look here. Its electronegativity will definitely be higher. So, in something called a haloalkane, or just take your normal haloalkane. I haven't gone to haloarene yet. I'll come to haloarene. Do you think haloalkane is polar or non-polar? Look here. Definitely, because the adjacent electronegativity is higher, it will pull its electrons. So, because it pulls, it will have a partial negative charge, and it will have a partial positive charge. So, because of that, what will happen here? Tell me. Because of that, what will happen? Polarity will definitely be created. Okay? Polarity has been created here. Okay? Polarity has been created. So, if this polarity is created, look here. If this X- goes out, in terms of chemistry, in terms of organic chemistry, what do you call this X-? You call it a nucleophile. Correct? Okay? So, here, either another nucleophile can replace this nucleophile, or if it's a large chain, a double bond can be formed. Only two things are possible. So, what possibilities are there in this haloalkane? Either nucleophilic, nucleophilic substitution, or elimination. Elimination reactions are possible. Do you need to memorize this? Many people memorize and study this. Seriously, I'm telling you. There are a lot.

of people who still mess it up like nothing, you don't have to memorize this concept. So, I've told you simply. Because I am polar, nucleophilic substitution can happen here. Or elimination can happen. Okay? Does anyone have any doubts about this? Shall we move on to the next one? Yes, shall we move on to the next one? Next. Everyone, write down another brainy point. This is actually a PYQ asked in NEET. So, I will give this to you as a brainy point. Questions have already come from this box twice. There's a chance it might be asked again. Okay? Questions have already come from this box, and again they ask questions from this box. Okay? So, come here, come, come, come, come. So, everyone write here, brainy point, brainy, brainy point. So, what this brainy point is going to tell is, the first thing here is bond length, bond length. So, its bond length, as usual, is something you know. The bond length of CF will be the least. After that, the bond length of Cl. After that, the bond length of CBr. After that, CI. So, the highest among them is that of iodide. Okay? Next, bond energy. Okay, bond energy. In bond energy too, your fluorine will definitely have more. After that, chlorine will have more. Okay? After that, after that, bromine will have more. After that, your iodine will have more. Okay? Yes, the least among them is iodine. In bond energy, if you come to the last one, it's your dipole moment. Okay, dipole moment, dipole moment. There's just a small change here. The order I am going to give here is an experimental order. What is it? Experimental order. Okay? A question has come from this in NEET once. Go and open the previous year's papers and see. You can see questions from this. Okay? First, what will come? First, what will come? Who will come first here? Right at the beginning, your Cl will come. Is it Cl? Then fluorine will come. Then fluorine will come. Then bromine will come. Then iodine will come. A question has come from this, and it is mentioned in NCERT. So, it is very, very, very important. So, is this box okay for everyone? Questions might definitely come again from this box. If it comes, many people will get stuck. If you don't want to get stuck, you have to study this. Okay? So, if anyone is watching without subscribing, without liking, please watch after liking and subscribing. Okay? So, next. So, if you come next, general methods of preparation. If it came in AIIMS, I told you it came in PYQ. But I forgot which AIIMS it was. AIIMS, AIIMS 2013? 2013 or 14? I don't remember correctly. But I remember it. It is in PYQ 2013 or 14. After 2010, we can go to the big ones. Here, for 2012. Super. I told you it came after 2010. I've told you correctly within that. Okay? So, if you come here, yes. In this lesson, you are not going to study any reaction from the preparation part that is exceptionally great. Most of the preparations are things you have already studied. But where do you think the question will mainly come from here? Yes, where do you think the question will come from? That is your, that is your chemical reaction. SN1, SN2, E1, and E2. There will definitely be a question from these four parts this year. I'm telling you again. You will have for sure a question in these four parts. I will put it in a single tabular column and break it into pieces. Don't worry. Okay? Yes, just one tabular column. Just one tabular column, and I will break down the entire concept into pieces. Okay? Just one tabular column. So, you don't have to worry. So, let's start with general methods of preparation. Methods of preparation. Okay? General methods of preparation. What's the story? See here, everyone, go back to the flashback. Flashback. Just one minute. Everyone, come to the flashback. In the flashback, in hydrocarbons, in alkanes, we prepared alkyl halides. What reaction did we use to prepare alkanes? Tell me, tell me, tell me, tell me. In alkanes, in alkanes, we prepared halo, halo, alkanes. But, but we saw that in chemical reactions. Chemical reactions. I'm telling you again. Organic chemistry is so simple that the chemical reaction of one lesson is the preparation of another lesson. The preparation of one lesson is the chemical reaction of another lesson. That's it, vice versa. You can check this. Most of the time, they wouldn't have taught you this. The preparation you are going to study here will be the chemical reaction of one lesson. A chemical reaction in that lesson will be the preparation of this lesson. Simplest, that's the core. Okay? So, the first thing we are going to prepare is from alkanes to alkyl halides. Okay? So, first, what is it? From, from alkanes, alkanes to alkyl halides. Okay? Alkyl halides. Okay? From alkanes to alkyl halides. First, we prepared it using the free radical mechanism. That is your free radical halogenation. Do you remember? So, the first thing we saw was free radical, free radical halogenation. Halogenation. So, in free radical halogenation, what did we use? Most commonly used was H2 in the presence of Cl2 or Br2. In the presence of Cl2, H2 in the presence of Br2. But look here, we had already solved questions for all of these. I am going to solve questions based on monochlorination again for you. But come here. One question. Between these two, which one did I say was selective? Which one did I say was non-selective? Which one was selective? Which one was non-selective? I told you one of them is selective. And I also gave you a question based on calculation. Which one has primary, secondary, tertiary? Find out. How many of you remember? Yes, here, your Cl is chlorination. Chlorination is non-selective. Okay? Non-selective. Selective. Your bromination. Anna, say hi. Hi, dear. Hi, dear. Bromination is selective. Okay? Bromination is selective. Chlorination is non-selective. You definitely need to know this one thing because I have already taught you this. I will give you a question. First, the question. Okay? Are you answering? Are you trying? Okay, come here. One question. See here. Hydrocarbon. Hydrocarbon. Okay? Hydrocarbon C5H10. Okay? Does not, does not react with chlorine. Chlorine in the dark. Okay? It didn't react in the dark. But, but gives a single, single monochloro, monochloro compound. Monochloro compound. Just one minute. Hello. Just one minute, guys. Okay, so come here. So, single monochloro compound. Okay? Okay? Single monochloro compound. H9Cl in bright sunlight. Bright sunlight. Okay? Identify the hydrocarbon. Today, there are going to be many questions. I'm telling you again. Because I have already taught you many things in preparations. So, by solving, let's do a lot of questions. Okay? So, start. Identify. Start. Identify the compound. Everyone, start answering in the comments. Quickly. Start, start, start. Identify the compound. Quickly, quickly, quickly, quickly, quickly. Okay? Quickly, dear. What did you eat? I ate vada in the evening. Cyclopropyl ethane? No. Next. A simple compound. A very, very simple compound. See here. If you give a compound with chlorine, and if that compound has primary, secondary, tertiary, is there a possibility for chlorine to react with it and give only one product, a monochloro product? With common sense, that's the first question. Tell me. With common sense, that's the first question. Tell me. If chlorine has tertiary, secondary, primary, etc., why is there no possibility of giving only one answer? Okay? It won't even mention monochlorine. It won't even mention monochlorine. Okay? Next. When you are given a question like this, the first thing to look at is the formula. It's in CnH2n. Akshaya, seriously. Only Akshaya has given the exact answer. No one else here has given the exact answer. I haven't seen the exact answer. Exact answer by Akshaya. Yes. If you look at CnH2n, there are only two possibilities. One is a double-bonded compound, or a ring compound. Okay? Ring-based compound. If there's a branch in the ring, it will go to other possibilities. Definitely, there's no possibility of monochloro. They have already said here, look, monochloro means that all the carbons are the same everywhere. Okay? Look here, only a single monochloro compound was obtained. So, what is the answer? This is the answer. Look here. No matter where you attach it, you get the same answer, right? Because there's no possibility with a double bond. Radical is finished. Did you do anything? Did you do anything for this question? Tell me. It's finished. The answer is here. First thing, how many of you were answering alkanes here? Giving the formula of the compound as CnH2n, and you're answering alkanes. That means you made a mistake in the very first step of the question, right? Did you people think that you made a mistake in the very first step? Right or not? It's a very, very least step. The first thing is to find out what the answer will be by looking at the formula. That's the main witness. If you misidentify this witness, what does it mean? Tell me. Can you misidentify that witness? That's the question. Now, didn't you even look at the formula? You should look at the formula first. How can you not look at the formula? Next, let's go to the next one. Another question for you. Okay? How many products on monochlorination? Okay, look here. Look here. Monochlorination means adding only one chlorine. What was the main hint here? Single monochloro. Now, think about it. What does single monochloro mean? It means, look here, whether you attack chlorine here, or here, or here, will the name of this compound change? Will all these compounds have the same name? Or do you think they will have different names? The names of all these compounds will not be different. It's the same name. Okay? So, everyone has a secondary carbon, right? Correct? So, when everyone has a secondary carbon, chlorine has no other possibility. So, single monochloro compound is finished. The answer is finished. You don't even need to think about double bonds. I'm telling you, don't even think about double bonds for the answer here. Okay? The hint point is, most of the time, if questions based on halogenation come, you have two possibilities. One is that it should be either an alkane, or if the formula given is for an alkene, then you should shift your answer to a ring-based compound. Okay? Yes. So, did everyone understand this well? Because last year, they asked a question based on monochloro, monochlorination, and many people left it, saying it was a JEE Advanced question. But I solved it once in my hydrocarbons. How many of you know, I don't know. It was a question solved once in hydrocarbons. But people, an advanced question, last chemistry. Okay? So, come here. How many monochloro? How many products are produced on monochlorination? Okay? Yes. Okay? On monochlorination, how many products will come? Single. Just one question. CH3CH2CH2CH3. Very, very, very, very, very simple question. Yes, C2. What is the answer? What is your answer? What will be your answer? Tell me fast. Only two possibilities. Yes, only two possibilities. Am I right or not? Only two are possible. One, one, CH3CHClCH2CH3. One plus CH. Put 2 here, ClCH2CH2CH3. Are there two possibilities now? Why are there two possibilities? Besides this, do you see any other carbon? Okay? In case, if a chiral carbon appears somewhere in this same question, what will you do? What will you do with the answer? Tell me. If a chiral carbon appears somewhere, if a chiral carbon appears at the place of attachment, I will change the answer to three. Because you have to consider the one with the chiral carbon as two. Answer. Okay? The one with the chiral carbon, there is only one compound, right? Its answer is two. Okay? Why is it there? Okay? Is it clear? Do you understand what I'm trying to say? Okay? Okay? Does anyone have any doubts about this? So, if a chiral carbon comes, you have to solve it like this. Okay? Very clear. So, questions like this are rarely asked, but still, if they come, it's a rare possibility. Okay? I don't think it will come this year. Okay? Don't worry. It's definitely not going to come. Okay? Next, from alkenes. From alkenes, what common reagent do we use for addition? To prepare from alkenes, what do we use? Tell me. We need to use two things for alkenes. One is C=C. Yes, from C=C, we use HX addition. One is to prepare your alkyl halide. Okay? So, your HX attaches here. Another thing we used was what? What else did we use? X2 addition. What is the common reagent we use for X2? Br2, Br2, CCl4. Do you remember or not? What addition did it do? Why? X2 addition. What addition did it do? So, here, one X, here, one X. Here, the bond. Okay? The most important point you need to know here is, just one minute. I'll make a box for this. Okay? So, here, in this, what is the one above? What is the one above? HX addition. Addition. What rule did we follow for addition? What rule did we follow for HX addition? What rule did we follow? Markovnikov's rule is followed. Yes, MK rule. MK rule is followed. That's one point. Second point. Did carbocation formation happen here? Did rearrangement happen? Of course, that also happened. Carbocation formation. Carbocation formation. Rearrangement. Rearrangement is possible. When I taught you hydrocarbons, I told you one thing. I told you that by studying this one chapter, I will teach you everything that comes in all the lessons. Do you remember? Have I taught you anything new so far? Have I taught you anything new from what I have taught so far? The only word from hydrocarbons is that everything from there is coming back here. I haven't taught you anything new. Okay? Come here. What about this? Anti-addition. Okay? What happens in this? Anti-addition happens. Okay? So, the most, most, most important thing here is the addition of X2. Okay? We can look at that through a box. You said, sir. You said, sir. Okay? So, in this box, write down the points for addition of X2 separately. Addition of X2. Addition of X2. Okay? So, if you look at the addition of X2, yes, commonly, if you have halogens attached next to each other on two carbons, what answer will it give? Always, if there are two carbons, and halogens are attached next to each other, what answer will you get? What type of halide is it called? What type of halide is it called? Tell me. First, write down the reagent. The reagent we used was Br2, Br2, CCl4. Okay? Br2 and CCl4. What did we use this for? What did we use it for? Used for test. Test for unsaturation. Used, used as a test for unsaturation. How does it use unsaturation? Reddish brown. What color did it change to? It changed to colorless. Okay? Reddish brown color changed to colorless. Okay? Okay? Next. Next. Adhini. It's been running for so long. I don't know what to do to gain subscribers. That's why they've brought all the boys from the NEET channel. Nothing else. So, next, what other point do you need here? Product. Product. What is the product? The product you always get is vicinal. Vicinal dihalide. Next. Do you all remember CSMTSR card? Do you all remember this? Does that apply here too? Suppose if I give a cis alkene and do this process, what will be the answer? If I give trans and do this, what will be the answer? What will happen if cis is given? What will happen if trans is given? Tell me. What will happen if cis is given? What will happen if trans is given? Hmm. What will happen if cis is given? What will happen if trans is given? Benzene. Why isn't it showing? There's resonance inside. How will it attack? It's also anti-addition. Definitely, nothing can be done. Benzene is strong. It's stabilized by resonance inside. So, how can it be here? You can also write this down. Benzene does not show this reaction. And last year, I told you that a question will definitely come from the test for unsaturation. I mean, this test. This test. I told you that a question will come from Br2CCl4. Note it down. A question will come. I also told you that a question will come from these two. And it came. And it came. That's the main, main thing here. Exactly that question came based on this. So, this reaction. You could have used common sense to answer it. Another point you need to note here is, if you give cis and do anti-addition, you get a racemic mixture. Racemic mixture. If you give trans and do anti-addition, you get, dear. Meso. That's all. The entire concept is revised. Is the entire concept revised in one box? Does anyone have any doubts about this? Does anyone have any doubts about this? Has the entire concept been revised in this one box? Okay? Just one question. I'm going to solve only two questions. Not many. After looking at that, we can move on to the next. Okay? Okay? If we finish preparation quickly, we can directly go to SN1, SN2. Okay? We are going to spend some time in preparation. We are going to finish preparation within 9:30. Okay? Okay. One type of bromocyclobutane. Yes, did everyone get the answer? One type of bromocyclobutane. Is it right or not? Simple question. Bromine here and bromine here. Okay? No doubts about this for anyone. Okay? Next, if you come, I'll tell you two reagents that confuse many people. Please note down these reagents. In addition of HX, addition of, just one minute. Just one minute. Just give me a second. Just a second. I'll make one call to mom. Hello. I'm talking on the phone. I'm going to talk. Oh, class is going on. Oh, nak nak nak nak nai nai nei nei. Nothing came in the mail. Nothing came. What are they doing? They're sending a machine? They're not sending that either. Nak means what? It means no. Did she ask if you wanted anything to eat? I said no. Only a few chapters are left. I'm finished with the syllabus. What? I don't understand what you're saying, Santosh. Okay, come here. Yes. Nahi, nahi, and nahi mean the same thing. Nahi, and nako also mean the same thing. Urdu. Do you know both Hindi and Urdu? Yes, I know. I can speak Tamil, I can read. I will definitely read. I won't read too much. I can read. Okay? I can read and write English well. Then, I know Urdu well. I can read Urdu a little. I can't read Hindi much. But I can speak Hindi well. Then, I can read Arabic well. Yes. I read Arabic well, but I can't speak Arabic. Similarly, I understand Malayalam a little. Yes. I understand Malayalam. I can speak a little. I speak slowly, slowly, slowly. Okay? I understand Punjabi a little. I understand Punjabi a little. I want to learn Spanish and Italian. Maybe in two or three years, I think I will learn. Because I have just taken a step. I have downloaded an app. I have downloaded Duolingo. I think I will learn both Spanish and Italian soon. Okay. Your watch is super, Anna. Thank you, dear. Thank you, thank you. How? Mallu. Mallu, actually, I watch a lot of Malayalam movies first. Okay? So, first, when I had a lot of time to watch, I watched Malayalam movies. So, I understand Malayalam quite well. Okay? And I used to go to Kerala from time to time. So, due to that collaboration, okay, okay, okay. Why are you laughing when I say Malayalam? What is there in Malayalam? Oh my God. Everyone study. Okay? So, come here. So, HX. HX in the presence of CCl4. Which one will attack? HX in the presence of H2O. Okay? If H2O is given, tell me what will attack. Look here, what is given below? What is this? Your non-polar solvent. Okay? Okay? Non-polar. Non-polar solvent. Okay? This is a non-polar solvent. Next, this is a polar solvent. Polar solvent. Do you think it will just sit there, looking at the polarity? Will it just sit there, looking at the reaction, a polar solvent? You guys, you both have fun. I'll just watch. It will definitely not be like that. Okay? So, here, a non-polar solvent will be like that, just sitting there, and what will it allow to attack? In this specific example, only X- will attack. Okay? X- attack will happen. But here, what attack will happen? OH- attack will happen. Okay? OH- attack will happen. So, because of that.

Many people make a mistake in this one concept. Next, after this one concept, there is another concept. Should we say Marconi anti-Marconi, Marconi, Audi, Marconi, or should we just proceed? Should we just proceed? Solve only one question. Solve this question. There will be nothing on Telegram, everything will be on the app. Notes and all. Okay, CH3, CH, double bond, CH2. Okay, at this point, I am giving HBr in CCl4. What will be the answer? I need the name of the answer. The exact name. I want the exact name of this compound. The exact name of this compound. Yes, at this point, CH3, CH, CH3, CH. Yes, here there is CH3. Put C in the middle. There is a double bond CH2. Okay, what is the name of the concept? Please tell me. Please HBr and CCl4. Please comment. Yes, at this point, at this point, actually, you have two possibilities. One possibility is that your Br attaches here. Another possibility is that your Br attaches here. Am I right or not? Yes, actually, that is not even a possibility. If we consider only the double bond, the possibility is that it attaches here or here. But actually, what happens is carbocation formation. What happens here? Here, carbocation rearrangement happens and it goes to this point. The carbocation will shift to this point. Okay. So, because of this shift, you will get your product here. In case I had formed Br here, what would you have named that product? What is the name of that unstable product? Chase, chase, someone asked what chase is. That is your Hoffman product. When you are getting an unstable product, that is called as Hoffman product. No, now what I got here is a stable product. So, this stable product is CH3. Here your CH3. At this point, a Br attached. Yes, your CH2, CH3. This is your, what product? This is your chase, chase product. Okay, next question for me is, what shift will happen in this compound? What shift happens here? Yes, what shift will happen in this one? Here, at this point, at this point, CH here. Do you think it will be stable if the carbocation is formed here? Or do you think it will be stable if it is here? Definitely, it will be stable in tertiary. But what is obstructing it from being in tertiary? Who is obstructing in the middle? The obstructing thing is this methyl group. Do you know what we will do with this methyl group? Like, "Brother, brother, brother, I and this person have come out. If you occupy both our seats, how will it be? Please move a little to the side. I will change your birth for you," like you talk at the train station when traveling on a train. You will talk like that and move the uncle aside. Okay. So, at this point, what will we do? We will take your answer and shift it to the uncle's birth, and then we both will sit here happily. Okay. Here your Br will come. Here your CH. Here your CH3. At this point, your CH3. Okay. So, everyone must have got an idea of what to do when given such questions. As far as I know. Did you get it? Did you people get an idea? Please let me know. We will go to the next concept. What is the next preparation? What preparation shall we look at next? Give me another question. Give me another question. Wait a minute. Another question. Another question. Just, just one more question. Wait a minute. I will be giving you one more question. Just a second. See, I am telling you again. In most lectures, they don't solve this many questions. When it is called a lecture, especially in chemistry. Okay. So, when solving questions, sit and solve them. Okay. Alright. What will be your answer? Where do you think it will attach? CCl4 is not needed. Just, just HBr. Here, this is a different concept. Now, at this point, will this HBr try to attack this OH? Or do you think it will try to attack here? Tell me. Do you think OH will try to replace it? Or do you think Br will try to attack here? Yes, when such questions come, don't disturb that. Disturb that guy who is out there with the pair. Okay. Just go attack that OH. Who is like sitting in the middle like a stone? What stone is it? They call it some stone. Like a standing stone. That OH is what you should provoke. You should not do anything with the double bond on the side. Okay. So, at this point, at this point, what should we do? We should attack with your Br here. This is the major product. Minor product. Next question. Is what I have written here the major product or the minor product? Is this the major product or the minor product? Tell me that. Is this major or minor? This is minor. Major. So, where is your major here? What is major? You know what is major? At this point, you should shift the double bond here. Wait. At this point, if your double bond shifts here, and if you attach your Br here, this is your major. Why did I call this major? This is your major. Okay. Yes. Tell me the reason why I am calling it major and this one minor. Here, look. At this point, if the double bond is here, how many alpha hydrogens are there in this? How many alpha hydrogens are there? How many alpha hydrogens are there in this? How many alpha hydrogens are there in this? After I shift the double bond, how many alpha hydrogens are there here and here? Here one CH3, here one CH3. Three alpha hydrogens. Three alpha hydrogens. So, a total of six alpha hydrogens. But can you people see that the double bond is here? There are no hydrogens on this carbon. Do you think it will be stable? Do you think it will be stable? No, it will not be stable here. Okay. So, that's all about it. Similarly, if you are given HBr and asked why we didn't attack here, look here. You have a double bond. Okay. At this point, you have OH. Is OH an easily leaving group or not? Tell me. Here, Br is a nucleophile. At this point, this is also a nucleophile. Okay. So, this will try to replace Br at this point. Then what will OH do? It will take H and go out as H2O. Finished. Understood? Yes, this is how things should be done. These are questions that can only be found in very standard books. Okay. You can only find this type of question in some books. So, people should solve this. Okay. Alright. Next, you have alkyl halide from alkyne. So, again, common sense. When you completely convert an alkyne into an alkyl halide, how many halogens will attach to it? How many halogens will attack it? Tell me. Tell me. Tell me. Tell me. Just one more question here. Just one more question. You are not visible. That won't be a problem. They will approve it. Don't worry. HBr, H2O. What will be the answer? What will be the answer? What is the answer to this? I need the name of the answer. I want the name of the answer. Tell me the name of the answer. I need the name. Where do you think it will attack? Your Br. Will Br attack here or here? It will attack at the first position. Bromine. Always. Because what rule will be used here? Anti-Markovnikov's rule will be used. So, your answer will be, at this point, your Br will attach. Okay. Anti-Markovnikov. So, bromine will attack at the first position. Next, come. Okay. So, here you have alkyl halide from alkyne. Let's finish it with one box. Yes, alkyl halide, halide, halide from. Okay. From alkyne. Okay. We are going to look at it. Okay. So, when preparing alkyl halide from alkyne, how many bonds will break completely? To break all three bonds, how many will you attack? Tell me. First, how many will you attack? You people are too silent. Two molecules. Okay. Four. What? What? Two molecules. Say the answer properly. Don't say it haphazardly. We will attack four halogens. Correct? So, come here. Come here for a minute. When doing HX addition, how many? Addition of X2. Okay. Four will go. In addition of HX, how many molecules will go? I mean, how many halogens will go? Only two halogens will go. Write both of them in the same box. Same box. Write it in the same box. Okay. Here, all of you, if you have studied hydrocarbons from me, this session would have been a quality revision session for you. If you came here without studying anything and just sat there blankly, then this session would be like, "What is this person saying?" That's all I can say. Okay. Please study hydrocarbons. So, first is addition of HX, and the other is addition of X2. Okay. So, in addition of HX, will you get geminal or vicinal? Will you get geminal or vicinal? Tell me the next point. Tell me. Tell me. Tell me. Yes, at this point, the first thing is that the MK rule, MK rule happens here. And syn addition is possible. Syn addition. Next, look here. CH3, C, triple bond, C. Okay. If I add HCl, CCl4 to this, what will you get? CH3, C, here one Cl, here one Cl, CH3. So, it will always give you geminal, geminal dihalide. Geminal dihalide. Okay. Geminal dihalide is always given. Next, in addition of X2, this is anti-addition. This is anti-addition. And what will happen here? At this point, you have CH3, C. Yes, at this point, triple bond, C. When the first molecule of X2 is added, you will get this. CH3, C, here one Cl, double bond, double bond, C, here one Cl. When the second molecule of X2 attacks, X2, put Cl2. Here also Cl2. So, when the second molecule attacks, you will be getting CH3, C, single bond, single bond, here one Cl, here one Cl, here one Cl, here one Cl. A total of four. So, what will you call this? Yes, vicinal dihalide. Dihalide or tetrahalide? Tetrahalide. Okay. Vicinal tetrahalide. Very clear. If everyone understood this very, very clearly, tell me. We will move on. Shall we move on? Shall we move on? Yes. So, next lesson. The first chapter is finished. What is the next chapter after that? What is the next chapter after that? What is the next chapter? It's alkyl halide. So, what are we going to do? We are going to prepare alkyl halide from alkyl halide. What are we going to do? Preparation of alkyl halide. Alkyl halide from alkyl halide. What do you mean by alkyl halide from alkyl halide? Look here. I already have an alkyl halide with me. I don't like that alkyl halide. So, I don't like what I already have. What will I do? I will replace it with something else. That's all. What's new about this? That's all. So, what are we going to do? Okay. So, we are going to replace what we already have. So, how are we going to replace it? The philosophy of life is that instead of us replacing, they will replace us and leave. You are something else. Oh, oh. So, in this, there are two naming reactions. One is Finkelstein reaction, and the other is Swarts reaction. Okay. Yes. Finkelstein reaction. Finkelstein reaction and Swarts reaction. So, here, look. CH here. So, Finkelstein. Finkelstein. Finkelstein reaction is one. The other is Swarts reaction. Okay. So, in Finkelstein reaction, is there I? Okay. In Finkelstein, there is I. So, I for what? I for chemistry. In this lesson, I for what? Okay, tell me quickly. In Finkelstein, there is I. So, I for what? Iodine. Tell me. Tell me. Iodine. Everyone. Okay. I for iodine. So, what are we going to do here? It's just a very simple naming reaction. We will have an RX. Okay. An alkyl halide. This alkyl halide, in the presence of sodium iodide and dry acetone. We will use dry acetone. What will we get? Alkyl iodide + NaOH. Okay. We will get NaOH, NaX. NaX. The condition is that at this point, at this point, the only condition is, what is the condition? This X should only be chlorine and bromine. It should not be fluorine. In case it is fluorine, will this reaction happen? If it is fluorine, will this reaction happen? Will it happen? It will not happen. Okay. This reaction will definitely not happen for fluorine because the electronegativity is too high. Next, in Swarts reaction, what will we replace? Tell me. Why do we use what in Swarts reaction? Tell me quickly. Swarts. In Swarts, you will have an RX. We will replace it with fluorine. Okay. Yes. AgF, H2F2. If any of these are given, you have to replace it with fluorine. SbF3. All of these will help you produce RF. How did I remember this? I will tell you. Actually, I had told this in the batch itself. Swarts. The term Swarts is somewhat analogous to the term 'pot'. Or is it? Pot. Swarts. Yes. So, F part. So, in Swarts reaction, fluorine will come. So, remember it like that. If you want. But I hope you won't forget it in such a bad way. Okay. Alright. So, okay. Next, Mridula Vedanthada has arrived. Has arrived. Hey, he has arrived. Slave has arrived. Hey, how much money? Tea and coffee? Or biryani? Biryani? Chicken biryani? Duck biryani? Okay. Next, at this point, I am expecting a question in NEET 2026. Okay. At this point, I am expecting a question from these naming reactions. You will definitely get a question. Okay. Please, please note it down. Okay. Next, next, you have alkyl halide from alcohol. We are going to look at it again. This is the same as what we saw earlier. Next is reaction with. Reaction with PCl5, PCl3. Okay. PCl5, PCl3, SOCl2. We are going to look at all of them in one place. Okay. PCl3, PCl5, and SOCl2. Okay. So, the main thing in PCl3, PCl5, and SOCl2 is, what will be the byproduct formed when it is with PCl5? What will be the byproduct formed with PCl3? And what will be the byproduct formed with SOCl2? When reacting with SOCl2, what is the name of this reaction? When it is reacting with SOCl2, what is the name of that reaction? Darshan? No, Darshan. Hey, hey, hey. What are you doing? In which world are you? Darzens reaction. Okay. So, here, what is it? Many people, how many people forget these byproducts? How many people get confused with these byproducts? Tell me. How many people don't even know how these byproducts are formed? I will get confused. Tell me. How many people? Because in one, there will be PCl3, in another, there will be H3PO3. How many of you have? How many of you have confused those byproducts? So, for that, what are we going to do? I am going to explain how they are formed. Look here. You have a CH3. You have an OH. Okay. What am I going to treat this with? PCl5. Look here. Watch carefully. This CH3OH will break. Demolish. It will break here. Okay. It will break here. Look, this broken OH will come to PCl5. Your PCl5 will always break as PCl3 and Cl2. It will break as PCl3 + Cl2. Okay. No one has any doubts until now, right? Now, this broken hydrogen, this hydroxyl group, it will come here and stand. Okay. This Cl2 is also ready to attack. Okay. This broken one. Okay. So, this PCl3 will say, "Come, oxygen. I need two bonds. We can form two bonds." And this Cl will run away with this hydrogen. Okay. It will run away with the hydrogen in the hydroxyl group. And only this one Cl will be crying "kwa kwa". At this point, what will be visible to his eyes? A CH3+ will be visible. What will be visible? A CH3+ will be visible to him. So, this plus group, it will attack on top of it, and they will all live happily as a family. So, what will you get here? CH3Cl + HCl + POCL3. Did everyone understand how this is formed? Yes. Look here. This is one product. This is one product. Okay. Sorry. This is one product. This is one product. And he is one product. "I am waiting for you, my heart is yearning," will sing this CH3. Next, shall we go? Next, PCl5. Okay. Everyone. Yes. PCl5. Okay. We can simplify this a bit more. For that also, we have a trick. If you give us the product you have, we will write it like this. CH3, here one O, here one H. We will write it like this. And then bring it down and write P, Cl, Cl, Cl. We will put one Cl here. We will put one Cl here. Now, what will we do to him? We will put a circle around him. We will put a circle around him. We will put a circle around him. Okay. If we do that, you will see three products. Like this product, like this product, like this product. Finished. How cool. Okay. Yes. So, you can study like this, and you can study like that. That's all. Okay. Yes. So, we can study this concept in any way. Okay. The shape is not right. I thought someone would say this. I knew you would say it. Next, come. In case, in this same concept, instead of giving alcohol, if they give its younger brother, ether, what should we do, sir? If they give ether, look here. There is a CH3 here. There is a CH2 here. Here one O. Here one CH. Conduct the class. CH3, CH2, CH2, CH2, put it. Put CH3. Come on, come on, come on. Look here. What is the answer here? You will get CH3, CH2, and then Cl + HCl + 1. And at this point, POCL3. That's all. Next, come. Next, come. Quickly, come. Quickly, come. Everyone study. Study quickly. CH3Cl. Here, what will you get? OH. + PCl3. Giving what? What? Come, come. Quickly, tell me the answer. CH3Cl + here what will you get? HCl + 1. + H3PO3. That's all. Finished. Next, next, come. Come quickly. Put chemical reactions here. Look, this is why you shouldn't do things like this in the comment section. When doing something, do it quickly. Do it slowly. Okay. So, coming to this point, yes. So, CH3, CH2, O, CH2, and CH3. Okay. So, in this, the same thing, you will be given PCl5. PCl5 will be given. Here, for this, we will take our PCl and C, three Cls, and put them like this. Okay. We have put three Cls like this. Like this one Cl. Like this one Cl. Okay. Why like this one Cl? Like this one Cl? At this point, we have to turn this into one product. We have to turn this into one product. Okay. Why won't both of them become one product? Now, we will give a connection between him and him. We have given the connection. Okay. That's all. Will HCl formation happen at this point? Definitely not. HCl formation will not happen here. So, 2 molecules of CH3, Cl2, Cl. Okay. Plus, at this point, you will get POCL3. Who is this? Hey, oh, oh. Okay. Alright, alright. Next, next, you have PCl3. Okay. So, let's look at PCl3. How many people have never understood why the byproduct of PCl3 is H3PO3? Why does H3PO3 come only from PCl3? How many people have not understood? Okay. So, come here. So, reaction with. Reaction with PCl3. So, with PCl3.

When doing a reaction, you see, I'll say it again, I'll say it again. Do you have CH3OH plus PCL3? Okay. So what needs to happen here is, look, you need to take a total of three, three moles of this. We took three moles of this. So in three moles, what will be separated is, it will separate into 3 moles of CH3. And 3 moles of OH will separate. Okay? Now, for three moles of PH3, what have we given? What have we given? Your CL3. We've given 3 CLs. Right? So what will happen is, they will all combine to form 3 moles of CH3 CL. So who is left? Three OHs are there, correct? What will these three OHs do there? They will go and attack this, and form PH3PO3. That's it, it's finished. What happened now? Here, these three together, this one, this one, this one, and this one will combine to form P double bond OH OH OH. So what will you get? What will you get? 3 moles of CH3 O CH3 CL P3 P3. Very clear, very, very clear, very, very clear. No doubts. Still very clear. If anyone has any doubts, please ask, friends. Come on, come on, come on. You can ask. Yes. Next, if you look at the intermediate, intermediate, CH3, CH3. Reaction with SOCl2. Okay. Reaction with SOCl2. SOCl. Look here, same CH3OH with SOCL2. The only small change here is that you will get all gaseous products. SO2 plus HCl. Since both of these are gases, they will fly away. Right? Why will they fly away? Because they are gases. So it is also called as Torsen's reaction. Okay? Torsen's reaction. If no one has any doubts in this, tell me, we can move on to our physical properties. Okay? So, physical properties of alkyl halides. Come on. Okay. Yes. Note one more thing here. Most efficient, efficient reaction. Okay. Reaction for preparation of alkyl halide due to high yield. Okay? Due to high yield, this is very important here. Okay? Hunsdiecker, I haven't taught it here. I will teach it in aldehydes. Aldehyde, green, scar, carboxylic acid, Hunsdiecker. I will be teaching. Okay. Next, what is in Hunsdiecker? So, next, if you come, physical properties. Physical properties. Physical properties of alkyl halide. Let's look at the physical properties of alkyl halide. What are you saying? So, alkyl, shall I go? Shall I go? First physical property. As soon as you start, this is what you need to study. First thing. Okay. First thing in physical properties, you need to study P3, P3. It's the same thing, man. Instead of PCl3, you're going to put PBr3. The same product will come. The same answer will come. Oh my god. Stereo, like, you can only say one prototype. Everyone can say it. The same byproduct will come. Instead of, instead of your alkyl, this, this bromine or iodine will go and substitute instead of chlorine. There isn't that big a doubt for you, tell me. Okay. So, coming here, alkyl halides are polar molecules. Okay? According to NCERT. So, alkyl halides are polar molecules. Okay? Polar molecules. And next, they are colorless. Okay? They are colorless. So, they will be colorless. And next, when they are pure. Okay? Right. Colorless only when they are pure. So, they will be pure. So, they will be colorless. After they spoil, they won't be colorless. So, what will happen is, they will get color. Okay? So, here, on exposure, exposed to light, due to oxidation. Oxidation, no. Just exposed to light. Bromides and iodides. Iodides become, become colorful. Okay? They will become colorful. Next, boiling point. Who will have a higher boiling point? Very, very, very, very, very, very important concept. So, coming to boiling point, here, who, who will have a higher boiling point? Normally, will alkanes have a higher boiling point, or will alkyl halides have a higher boiling point? Boiling point. Will alkanes have a higher boiling point, or will alkyl halides have a higher boiling point? What is this, man? You're sitting like you're dead. In the comment section, I'm asking questions. Everyone is sitting silently. Oh my god. What will you do? Honestly, I don't understand. Tell me something. If you tell me to say something, the comments will come with a bang, bang, bang. If you tell me to say something, the comment section will just go on and on. Oh my god. Okay, okay, man. Okay. So, coming to boiling point, your, your alkanes, compared to alkanes, okay? Alkyl halides, halides have more boiling point. Boiling point than, than alkanes. All that is coming. You are just commenting slowly. Than, than alkanes. What is the reason for this? Reason? Why? Reason? Look here, write reason, small reason. The reason is, in your alkanes, because they are nonpolar, there will only be London forces. London, London forces. London forces, which is weak. Very weak. Okay? Very weak forces. But in your alkyl halides, okay? Right. In alkyl halides, what will be there? Here, it is polar. So, because it is polar, what is it? Dipole-dipole interaction. Dipole-dipole interaction will be higher. Okay? So, this dipole-dipole interaction. So, if they ask you, there is a chance of asking this in assertion reason or statement-based questions. Okay? I'll say it again. Assertion reason, or did we discuss this? Or I didn't tell you this in chemical bonding at all. Okay? Yes. There is a chance of it coming in assertion reason or statement-based questions. Next, similarly, your boiling point order, if you look, RI will have a higher boiling point. I, yes. Okay. Yes, that's what it is. I, then RBr. After that, RCl. Okay? After that, RX. Okay? So, RX. This is why it is like this for this. Yes, come on, man. Come on. Everyone come. Now everyone will come. Tell me what I is. Tell me. Oh my god. RI is not "Iyas", it's RI. You are imagining some other name. Very, very bad. So, here, this boiling point is directly proportional to molecular weight. That's why this came. Okay. Note one more point. Boiling point is inversely proportional to branching. Okay? As branching increases, boiling point also increases. This is a concept we have already taught. Okay? Next, solubility. Solubility. So, in solubility, alkyl halides are polar. So, they are slightly soluble in H2O. Since alkyl halides are polar. Okay? Right. Polar. Okay? They are slightly soluble. Soluble in water. Okay? There will be some solubility in H2O. Okay? Because of the formation of hydrogen bonding. Okay? The order, if you look, so, the order, if you look, your R, after that, RCl. After that, RBr. After that, RI. Okay? So, this is the order of your solubility. Right? So, if everyone is okay with this, tell me, we can move on. After this, we can directly jump into chemical reactions. Yes. Take a break for 5 minutes. Because I have put my pen on charge. Okay? Take a break for just five minutes. Just five minutes. Anna, I have completed the 12th syllabus revision using the old lecture of 2025. Now, what should I need to do? Should I need to watch new lectures again? Because there are new topics in 11th. Notes. Revise them. Or if you need to revise, watch the lecture again. Just go through your questions. Solve more questions. Watch question-solving sessions. Okay? See how to approach questions. That one thing. Go on, don't stop. For one chapter, minimum, you should solve. It's not like, how to say, you have to solve this much. There's no such thing. You have to solve different, different cases. You have to solve until you feel it's enough. It's a condition like, minimum 150, 200 questions, probably. No dinner. No, no dinner, ma. Is this girl watching the class, or what is she doing? She doesn't seem to be asking doubts, but she's coming in correctly in the middle. Should I tell you something? What should I tell you? Why go and eat? No, I won't eat. Waiting for March surprise at night. Hey, man, March hasn't even ended yet. She's asking for a March surprise. How? Doctor, don't do that. I'm a doctor. Who is so affectionate towards me? I don't understand. Even my parents aren't this affectionate towards me. Who are you? Is the NEET application closed? I don't think it's closed yet. Your lectures are the reason for scoring well in chemistry. Thanks, Anna. Super, ma. Super. Keep studying like this, ma. Super, ma. Come on, come on. Today, Tesla score is 110. Super, ma. Super. Very, very good. Very good. You should solve it perfectly like this in NEET too. Okay. My back ID, Karthik, is that you? I know, man. Did you see it or not? Karthik, you have no shame, right? First, I got 145, 165. Super, ma. You all seem to be studying intensely. What did I miss? Oh, Karthik, back ID on YouTube. Okay. Someone messaged on Insta with the same name. Is that you too? Then, someone messaged on Insta with the same name. Then who is that? Who is that? Is it him? It's not me. Then who is it? Hey, what's happening here? She's asking. Tell me. Tell me. What's happening here? I don't know, ma. Who? What is this? Very bad. What are you saying is very bad? You study. You study for the exam. Brinda, okay? Don't do this. Don't look at these people. You study. Come on. You study. Brinda. You study. Okay? Okay, dear. Super, super, ma. Super, super. Okay. I will help you. I will help you study. Don't worry. Oh my god. If it's a joke, it's not a joke. I don't understand. What don't you understand? Are you going to come as back ID too? Oh my god. Okay. Yes. So, come, come, come. Let's study. Okay. Come. Okay. These people will not let you study. Okay? So, don't get distracted. Please. Okay? Okay. You carry on. Only one month left. If you don't revise, it will definitely be like this. Bye, ma. Bye, bye, bye. I also message on Insta. On which account did you message? I have three accounts. Tell me which one you messaged on. If you message on Riyas, I will reply most of the time. If you message on Snap, I will reply. But if you ask doubts on Snap, I won't reply. If the message is on my WhatsApp number, I will reply. If it goes too far down, I won't know. Now I'm checking. What else, ma? You are speaking everything wrong. Chi chi. If it's like this, what is this? Anna, do you maintain streaks? I do. But, how to say, if I add someone, I will reply after a month. I am that slow. Because I am not active. Active, meaning, I am active in sending snaps. But I am lazy to add others. I don't get time. Hey, hello, hello, hello, hello. Thambi, hello. How is your preparation going? Are you studying at home, or where are you? Streak? You don't know what a streak is? That beep, beep, they eat it by cutting it. That's a streak. You don't know what a streak is? Anna, please continue studying. Man, I'm sitting here with the charger plugged in. I'm not just sitting. Next, I have to conduct chemical reactions non-stop. If I sit with the charger plugged in, please continue studying. He's putting a shot. No, sir. I am in Kerala. Oh, you are in Kerala? Super, super, super. Anna, when will you study? I won't study. I touch books only once a year. I won't go to university exams. I open books and study. Then I take the exam and pass. I move on next year. Finished. Top revision idea. Tell me. Now, streaks, maintaining streaks. I normally send 10 snaps a day. You know, most of them are who? In those snaps, my cuties, my babies will be there. Zara, Basa, they will be there mostly. Mostly cats will be there on Snap. There will be more cats on my Snap. Wait, man. The charger is finished. Only when it's charged can I start. If you want, I'll show you a video. Wait. I'll show you another one. Wait. Oh my god. I can't find the video I took. Look here. Look at this. Look at this. I have five cats like this. I have five cats. Today, why are you so beautiful, Riyas? Who is this? Who is this new person? Don't you like dogs? Actually, I want to raise a dog, but in Islam, you're not supposed to, so I haven't. That's it. Shall we start? Yes, shall we start? What is this? This girl is always causing trouble. It stopped at 72. Now. I paid so much money, and he's cheating me, the Apple guy. Go to Gilli? Who is that? Why go to Gilli? Okay. So, come here. Chemical reaction. Very, very, very important topic. A question will come from this in NEET 6, 100%. 100%. Okay? Yes. So, chemical, chemical reactions of alkyl halide. Okay. Chemical reaction of alkyl halide. Right? In this, you are going to study a total of five, five things. Okay? Five things you are going to study in this. What are you going to study? Nucleophilic substitution, one. I said at the beginning, alkyl halides undergo nucleophilic reactions. Elimination reactions, remember or not? Remember or not? You are going to study three things in this. One, nucleophilic, nucleophilic reaction. Another one is nucleophilic substitution reaction. It's correct to write substitution. Next, elimination reaction. Elimination reaction. Next, elimination reaction. Then, reaction with metals. Reaction with metals. So, reaction with metals. Okay? Right? Okay. So, here, in nucleophilic substitution, you are going to study two. In elimination, you are going to study two. Okay? Reaction with metals, there are not two or three. Reaction with metals, there is only one. Okay? So, in this, what are you going to study? What are you going to study in this? You are going to study SN1 and SN2 reactions. Yes. SN1, SN2 reactions. In this, you are going to study E1 and E2 reactions. E1, 1 reaction and E2 reaction. Okay? So, here, SN1 and SN2. In this, E1 and E2 reaction. Okay? Right? So, SN1 and SN2. This is E1 and E2. E2 reaction. This is SN1 and SN2 reaction. Okay? Right? So, SN1 and SN2. How many people dislike this topic? How many people say, "I have studied it, but I get confused"? How many people are there? Because there are a lot of people who have never studied this properly. So, because of that, many people will not have studied this properly. Before studying SN1, SN2, you need to study two things. Okay? You need to know two things. Draw a big box. In this big box, we are going to look at two things. What do you mean by polar protic solvent and polar aprotic solvent? What is a polar protic solvent? What is a polar aprotic solvent? We are going to look at that. Okay? So, one, what is a polar protic solvent? Actually, what is a polar solvent? First, what is it? Will the dipole moment be zero or not? Tell me, tell me, tell me, tell me. In polar solvents, will the dipole moment be zero or not? It will be non-zero. Definitely not zero. Okay? The subclasses of polar solvents are two: polar protic and polar aprotic. Okay? If you know about these polar protic and polar aprotic solvents, only then can you find the difference between E1, E2, SN1, SN2. So, write: polar, polar protic solvent. Polar protic solvent. Polar aprotic solvent. Polar aprotic solvent. Okay? Polar protic solvent. Polar aprotic solvent. Here, how do you identify a polar protic solvent? First thing, your hydrogen atom, with whom will it be attached? The hydrogen atom is directly attached to a highly electronegative atom. Okay? It will be attached to a highly electronegative atom. Here, the hydrogen atom is not attached to the, not attached to the high, highly electronegative atom. Did you understand both of these? Yes. I'll give examples of this. And I'll tell you one more thing here. Listen. The most common example here is H2O. Is H2O a polar protic solvent or a polar aprotic solvent? Take H2O. H2O. H2O. In H2O, H is attached to O and H. With whom is H attached? Look carefully and tell me. Look here. With whom is H attached here? With whom is it attached? It is attached to a highly electronegative compound. Correct? Everything like this will come under your, what is it, polar protic solvents. Right? Similarly, coming here, DMF. DMF, yes. D M O. After that, D M. After that, D H F. Okay? All compounds like this will come under polar aprotic. DMF means what? Dimethyl formamide. What is dimethyl formamide? Dimethyl sulfoxide. What is it? Dimethyl acetamide. I'll give only one example here. Come, I'll give two examples. You can look up the rest in the book if you want. Okay? So, D H F. You will definitely know Tetrahydrofuran. Yes. Tetrahydrofuran. You will definitely know it. Look here. In this, is your hydrogen attached to oxygen anywhere? Oxygen is the highly electronegative atom here. But is it attached to it anywhere? No. Okay? Similarly, look at DMSO. What did I say DMF is? Look here. Dimethyl. Yes. Dimethyl sulfoxide. Dimethyl sulfoxide. Look here. In this, your hydrogens are attached to carbon. But is hydrogen attached to a highly electronegative atom? No. So, wherever your hydrogen is not attached to a highly electronegative atom, all of them are your polar aprotic solvents. Clear? Did everyone understand this? Did everyone understand this? Tell me if you understood. We'll move on to the next topic. Okay? Tell me if you understood. We'll move on to the next concept. Shall we proceed? Okay. Let's proceed. So, now, where are we going? Directly to what? We are going directly to your nucleophilic substitution reaction. Okay? Everyone, write the heading. Nucleophilic substitution reaction. Okay? Nucleophilic substitution reaction. We are going to do it. So, what is nucleophilic substitution reaction? It's nothing big. In it, you have RX. When this RX is near a nucleophile, look here. We are going to replace one nucleophile with another nucleophile. That's all. Nothing else. Who is the nucleophile here? Here, it has a partial positive charge, and it has a partial negative charge. The nucleophile will come here and substitute this. In the presence of a solvent. Why in the presence of a solvent? We are just going to replace it. RX + X-. The solvent used here determines whether it is SN1, SN2, E1, E2. Everything is here. Okay? Yes. Correct? Okay. So, before that, we will look at a very important reaction that has a chance of being asked again in NEET. It has been asked before and has a chance of being asked again. Okay? Right? So, look here. When RX reacts with these four species, what will happen? You need to tell me the answer quickly. Quickly, quickly, quickly, quickly, quickly. Okay. Is KCN ionic or covalent? Potassium is there. Do you think it's ionic or covalent? It is an ionic species. Ionic species. So, it will separate into K+ and CN-. So, C triple bond N. To whom will the negative charge go? It will go onto your carbon. So, who is going to attack here? Carbon is going to attack. So, R C triple bond N. You will get cyanide. Cyanide. Next, look at AgCN. AgCN is covalent. So, because it is covalent, do you know whose negative charge it is? There is no charge. What will happen is, the lone pair on your nitrogen here, the lone pair on nitrogen will attack. So, because the lone pair attacks, what will be formed here? R C triple bond N will be formed. This is isocyanide. This is your isocyanide. Now, do the same for KNO2 and AgNO2. Let's see. KNO2 will also form K+ and NO2-. It will be formed by oxygen attacking. Right? Whereas in AgNO2, the lone pair on nitrogen will attack here. So, because of this, what will happen here? RNO2 will be formed. This one is nitroso. This one is nitro. This one is nitroalkane. Okay? Right? Alkane. It is a very, very, very, very, very important concept. Diversify. Please put a star mark on this. They will ask this question frequently, which is confusing. They will ask, they will ask, they will ask. So, now, SN1, SN2, E1, E2. NEET commander. Are you Trisha? Or is it Sara? No, man. I am single. Trisha is not there. What is your wife's name? Vijay's wife's name. Sangeetha is also not there. Sangeetha is not even there. How would I have gotten Trisha? What are you saying? First, first, there should be Sangeetha. Only if there is Sangeetha can Trisha come. You tell me. What to do? Okay. Come here. Printout? No chance of a printout. At this young age, what are you saying, sir? We have seen a lot, man. We have seen a lot. After seeing, we are sitting silently, saying no. Okay. So, come here. So, come here. Types of nucleophilic substitution reaction. Types of types of nucleophilic. Nucleophilic substitution. Okay? Right? So, what are the types of nucleophilic substitution? Tell me, tell me, tell me, tell me, tell me. What are the types? There are only two types. Okay? Only two types. One is SN1, and the other is SN2. Okay? So, why is it called SN1? Tell me the full form of everyone. Everyone, tell me the full form. Tell me the full form of SN1. SN1, SN1. What is the full form of SN1? Hi Abhinash Priya, I love you. Hey, he's a boy. Who is this? He's proposing to a boy. What is happening here? Hey, what are you doing? Oh my god. What is this color? Didn't I change it? Didn't I change the color? I'm scared of you all. God, save me. SN1. What is SN1? Unimolecular. Uni molecular. Unimolecular nucleophilic. Nucleophilic substitution. Substitution. Why is there no tuition from any sister? No sister's tuition? They have put substitution. Oh my god. Everywhere, only sisters teach tuition. What substitution have they put here? Very funny joke. Okay. Okay. Okay. Right. Right. Yes. So, substitution. Substitution. Okay. So, look here. Here, yes. Actually, what happened today? On my bus, a girl said, "I'm telling a joke." She said, "Riyas, Riyas, listen." So, I listened. Okay? What happens if you build a bridge before the beach? She asked. What?

I asked if it was okay. He said, "Tell me, you tell me." I asked what would happen if a bridge was built in front of the beach. I was thinking, I don't know, tell me. The girl said, "Will it cost money?" Will it cost money if a bridge is built in front of the beach? It will cost money. After saying this, she herself laughs. I got annoyed. I'll put it in class today, I'll tell a joke today, and then I left in frustration, saying it will cost money, and she laughed, saying it will cost money, and then she left with a loud laugh. Okay, so in this, you see SN1, you look at all the ones above, and here, look, write it like this, come back in reverse. Everyone should always go from reverse. Go forward from reverse in life, okay? Yes, it's like that. So here, look, first what is there? One is there, unimolecular. Next, N is there, nucleophilic. Third, S is there, substitution. So unimolecular nucleophilic substitution. Next, when you come here, yes, next when you come here, next is your SN2. So SN2, similarly, what should you put for 2? Bimolecular. Then what should you write? Nucleophilic. Then substitution reaction. Super, yes. Did everyone write it down, friends? Does anyone have any doubts, friends, friends? Tell me, come on, come on, tell me. Okay, everyone has put this. Now what are we going to do? We are going to put boxes. Everyone, everyone, can we put boxes? Yes. So here we are going to put a box. We are going to put another box after this box. Okay? So come here. Okay, did everyone put the box? Yes, the box is put. Okay, the box is put. So in this box, write SN1 at the top. Write SN2 here. Okay? We are going to copy and paste this box. Copy and paste it. Anna, I got to understand it and study. You understand, okay? Okay, sir. 720 is still possible. So come here. So when you come here, here, why is the first difference between your SN1 and SN2 only one? Okay, only one difference. The first difference you need to know is, yes, it is, it is, only the name is unimolecular, but how many steps is this process? How many steps is this process? How many steps is this process? Tell me, tell me, tell me. Tell me. This is a two-step process. Two steps, like verification, a two-step process, a two-step process. Okay? What is this then? This is a single-step process, like me. Okay, so SN2 is a single one. It is a single, single-step process. Okay, a single-step process. Okay? So next, when you come here, here, why do I say it's a two-step process? Listen. Here, your R-L, what does L mean? L means your leaving group. He is the one who is going to leave now. So R alone, or with something else? Okay? Okay, he is the leaving group, leaving group. Okay? Okay, leaving group. As soon as you see this leaving group, you can't just say, "Go, come on, get in the car," and take them. Okay? Okay? First, we will approach by saying, "Hi, this is Riyas, how are you?" Okay? Why, as soon as you come, you say, "Come on, get in the car, hey, come on," and you shouldn't force them. So SN1 is a smooth process. First, you have to talk, talk to them, and ask them how they are, yes, and make them laugh by talking to them for a few words. Make them laugh, and then we ourselves will make them laugh again. When you do all this, they will think, "He is the one who is filling our sorrow," and they will come to an intermediate stage. Okay? Okay? At this point, okay. At this point, what happens? Yes, carbocation formation happens. Why are we doing all this? Because he already has someone, right? How can you go? There is already someone there. If you go and manipulate someone who already has someone, it will break first. Okay? So, we have now broken the one who already has someone. Come on, get out, get out, I'm coming in, and we have now broken it. At this point, L, the leaving group, has gone out as a nucleophile. Okay? It has gone out. Now, when it goes out, what will you do? You will stand aside and watch. "I'm coming," and a nucleophile is waiting here. What will this nucleophile do? It will replace our leader. What happened here? At this point, R-Nu has undergone substitution. Look here, this is your, then you say, "Go, go, why are you reminding me of this, God?" Yes, this is live. Yes, ma'am, this is live. Why, ma'am, understand. When you come here, this is step one. This is your step one. Okay, poor thing, he will be dying here unknowingly with that psycho. Step, this is step two. Okay? Now look here, at this point, will this breaking process happen quickly, or will this happen quickly? Look here, they were already in a pure love. You have to break that love. So how patiently do you have to wait? So, who is the rate-determining step here? He is your rate-determining step. He is your RDS, the slowest step. Okay, the slow step. Why is it the slow step? This is the slowest step there is. After this, if it breaks, that's it. After that, it's easy to correct. It takes about a month to correct. In a month, we can correct it and proceed with our reaction. Okay? So, when you come here, so when you come here, this breaking process is very difficult. Okay? So, once we finish breaking, the next step is easy. Okay? So next, when you come here, in SN, none of this will happen. You will stand there and say, "Do you know what your person told your mother?" and like stabbing him in the back with his own person, we will say something like, "Your person spoke wrongly at your house," and break it there, and then I will give you defeat. This is what we are going to do now with our SN2 reaction. Let's go, take the nucleophile, do the reaction, and go to the next step. So, in one step, okay. Love at first sight, it's over. Okay? So, you went, gave defeat, finished the love, and confirmed it. That's it. So, what happened here? Here, R-L will come. Similarly, R-L has come. So, this R is your leaving group. Here is the nucleophile, yes. So, at this point, what will happen? It happens in one step. He will be standing on the road, watching. Why are you calling Livin on the road? Oh my god, hey Livin, Livin, who is he? Hey Livin, oh my god, oh my god, Livin, who is he? Oh my god, why is that boy saying "I love you" to you? Oh my god. Okay, so at this point, it happens in one step. So, this one step is your RDS. No one has any doubt about this, right? This one step, this single step is your rate-determining step. There is nothing here, because he came, he came, he chased him away, he put him, that's it, the product is finished. Okay? So, at this point, when he came, he shot, he died, repeat. Similarly, at this point, what happened? He came, chased him away, he came in, formed the product. Okay? This is what happened. This is what happened now. So, so, so, at this point, please don't remind me of that. I'm laughing. Okay? So, when you come here, you will tell the order of that specific reaction based on your rate-determining step. Did everyone study the chemical kinetics chapter? Okay? You must have studied in the chemical kinetics chapter. So, in the chemical kinetics chapter, you have studied that your RDS determines the rate of that specific reaction. Okay? So, at this point, look here, your rate, at this point, the rate is directly proportional to who is here? Who is here in the RDS? Tell me quickly. Who is in the RDS? Look here, this is your rate-determining step. Okay? I have written what needs to be written here. Okay? So, only R-L is here. What is its power? You have one in its power. So, if there is one in the power, the order is how much? The order is also one. Because the power is one, we call him what? We call him what? Because the order is one, we call him unimolecular. Correct? This is the reason why we call it unimolecular. Next, when you come here, look here, look at its rate. Rate is directly proportional to R-L and the concentration of the nucleophile. Both are there. This is one, and this is one. So, what is the order here? What is the order here? You all know it. 1+1 is two. So, that's why you call him bimolecular. Okay? He is unimolecular. Okay? Another question I will ask. Come here. Your rate depends only on whose concentration? Whose concentration does the rate depend on here? It depends only on the concentration of the reactant. Okay? This rate, the rate depends only on the concentration of the reactant. Okay? This rate, the rate depends on both the concentration of the reactant and the product and the nucleophile. Nucleophile. Okay? Reactant and nucleophile. Or you can also write this as substrate. Yes, substrate. What, Livin, is he in hiding? Okay, substrate. So, what am I asking? Can we plot a graph here based on this? What kind of graph do you think will come? Why, there are only two graphs here. Okay, okay, leave it. I would have been happy if a girl had said this. Since a boy said it, I can't be happy. Okay? So, come here. First graph is rate versus nucleophile. Rate on this axis, nucleophile on this axis. First graph. Here, rate on this axis, and your substrate R-X on this axis. Okay? This is your substrate. So, tell me, how will the first graph come? How will the second graph come? How will the first graph come? How will the second graph come? First graph. Look here, in the SN1 reaction, does the rate depend on the nucleophile? Does it depend on the nucleophile? Definitely not. Okay? Definitely not. So, a constant line graph will come. Here, look, it is directly proportional. So, a straight line graph will come. Okay? If we draw this graph here, if we draw this graph here, what graph will come for both? The same graph will come for both. Because it depends on both. Look here, rate versus R-X concentration. This is rate versus nucleophile concentration. What will happen here? Straight line. Straight line here too. Okay? Yes, very, very clear. Does anyone have any doubts about this? Does anyone have any doubts about this? If you don't have doubts, tell me, we can move on. Yes, favorable conditions for SN1 reaction, SN2 reaction. Favorable conditions. So, favorable conditions, yes. First, reactivity. Write reactivity. Reactivity R-X. Yes, tertiary alkyl halide, then secondary alkyl halide, then primary alkyl halide. Okay? This is a major thing for you. Next, next, weak or neutral nucleophile. Always, what should be here? Weak or neutral, neutral nucleophile favors SN1. Okay? Next, next, when you come here, conditions. Okay? Favorable conditions. First, reactivity. So, in reactivity, what reactivity will come? For this, primary R-X, then secondary R-X, then tertiary R-X. Okay? Does anyone have any doubts about this? Next, the next point, strong nucleophile. Okay? Strong, strong nucleophile with high concentration favors SN2 reaction. Okay? If there are no doubts about both of these, tell me, we can move on to the next point. Solvent. What solvent are we going to use here? Yes, solvent. What solvent are we going to use here? Solvent. Solvent. Here, polar protic solvent. Okay? SN1 will happen in polar protic solvent. Here, what solvent are we going to use? Polar aprotic solvent. Okay? Protic solvent. If you understand all of this, tell me, we can move on. Move on, move on. Shall we proceed to the next concept? Yes, can we move on? Can we move on? Can we move on? Okay, in this, will racemization happen in SN1? Will racemization happen or not in SN1? Yes, will racemization happen or not? Write this. At this point, write racemization is possible. Yes, formation of, formation of racemization. Okay? At this point, what will happen? Backside attack will happen. So, because of the backside attack, the whole thing will turn like an umbrella. What will happen like an umbrella? It will turn. So, because it turns like an umbrella, what will happen here? Complete inversion will happen. Okay, complete inversion takes place. I will explain this. Come here. I will explain by drawing the reaction. Come here. Come here. Your reaction will happen like this. First, I will tell you this. Look here, you have C, here you have R1, R2, R3. Here you have X. Okay? Or not like this, wait a minute. Here you have R3. Yes, here R2, here X. Okay? What will happen in this is, he will come, a nucleophile. This nucleophile will come from here and attack from the back. He will look at which side the bulky group is not on and attack from the back. He will attack with a force, right? As he attacks, he will start to leave. So, because of this, what will happen to this shape? Everything on this side will go to this side. R3 will come like this. R2 will come like this. R1 will come like this. The one who is attacking here will attack at this point. Okay? Like an umbrella, how it comes, like in the rain, if the wind blows, the umbrella will do this. Because of that, it has a name: also called as Walden inversion or umbrella inversion. Umbrella inversion. Okay, umbrella inversion. Did everyone understand this? Next, when you come here, in the case of SN1, this is C. At this point, there is a Br. At this point, there is an R1. At this point, there is an R2. And here is your, here is your R3. Okay? In this, there are two attacks possible. First, what will happen? What formation happens first in your SN1? What formation happens first? Carbocation formation happens. Okay? So, carbocation first formation happens. So, here R1, here R2, here R3. Okay? First carbocation formation happens. After this carbocation formation is completed, there are two possibilities. Okay? Your nucleophile has two possibilities. It will attack in two possible ways. Okay? So, it will attack in two possible ways. One is attacking from above, and the other is attacking from below. One is top attack, and the other is bottom attack. Okay? One is top attack, and the other is to push him out from the front. Or else, to stab him in the back. Okay? For that, we can just do it in front. So, what will happen at this point? Carbon in your top attack, here R1. Okay? Here R2, here R3. R3. At this point, your nucleophile will attack. Okay? At another point, at another point, a similar thing. Here is the nucleophile. Okay? At this point, your R2, at this point, your R1, at this point, your R3. Look here, is the product formed above exactly the same as this product? Yes, can you see it or not, all of you? Look here, are this product and this product the same? So, his name is retention. Because he remains as it is, this is retention. This is the retention product. Now, look above. Is the product formed above exactly upside down? Because of this, what is his name? Inversion. What is his name? Inversion. So, at this point, look, two things are formed. What is racemization? In a racemic mixture, you will have pairs of enantiomers formed in the same way. So, at this point, a similar thing will happen. Because both are opposite to each other, and because it is chiral, there will be many chiral centers available here. Okay? So, therefore, both racemization and inversion take place. Both racemization and inversion. Inversion plus retention. Retention. All of this is possible here. Possible, possible, possible, possible, possible. What about the percentage? Percentage-wise, 45% retention will happen. 45% retention. 55% inversion will happen. Okay? 45% retention will happen, and 55% will happen, inversion. Okay? Does anyone have any doubts so far? Does anyone have any doubts so far? If you have any, please ask, we can move on. I will ask a question. Answer this. Find the SN1 reactivity. Before that, I haven't mentioned two cases. Okay? Okay, so come here. In this box, write a brainy point. So, what is the brainy point? First, first case, C-Cl, double bond C, here X. What is this? Vinyl. Yes, vinyl. Vinyl halide. Vinyl halide. If you look closely at this point, what will you have here? You will have a lone pair. Okay? At this point, will resonance be involved or not? Will resonance be involved or not? So, if resonance is involved, if there is a partial double bond character here, will it break easily? Will it break easily? Definitely not easily. So, in SN1 reactions, if you are given a vinyl halide anywhere, please note it down and answer. In any vinyl halide, SN1 reaction will not happen easily, will not happen, will not happen. Okay? SN1 is not easily possible. Okay? So, mention this point. Next, I will give you two questions. Try to answer these. Arrange the SN1 reactivity. Before that, I will tell you where SN1 will occur and where SN2 will occur in secondary halides. Wait. Suppose a secondary halide is given, then you have to look at other things. Okay? So, just, just give me some minutes. I will put a tabular column and tell you where SN1 will occur and where SN1 and SN2 will occur. Okay? So, come here. The first question is CH3CH2Br, CH2 double bond CHBr, CHBrCH3. Next, CH2 double bond CBr. Then CH3CHBrCH3. What will be the order of reactivity? 1, 2, 3, 4, 5, 3, 4. Tell me the order quickly. Try to answer this question fast. 2, 4, 1, 3. 2, 4, 1, 3. Yes, is everyone getting the answer 2, 4, 1, 3? Why do you all think the second one will be more? Everyone, why do you people think the second one is more? Second one is more. Yes, it is having resonance and more stable carbocation formation will happen. Look here, at this point, if carbocation formation happens, it will be very stable, right? It will be very stable. Here, there is no partial bond character, but if carbocation formation happens here, it will be very stable. Carbocation formation proceeds through SN1 carbocation formation. Okay? So, definitely, at this point, 2 will be more than 4. After that, after that, what else is there? The first one will happen easily. The last one is the third one. Because, the third one, I just told you a little while ago, is it vinyl? Is it vinyl? A little while ago, I gave an example. It's the same example I gave here. So, next, come here. In SN1, SN2, everyone can solve very basic examples, but many boys, you see, if such questions are asked in some tests, they write them incorrectly. Right or not? You solve this easily, but in solving such questions, many people make mistakes. So, look at this properly. Next, at this point, CH3 twice CL. One, C6H5 CH3 twice CL. Next, CCl3 CCl3 twice CL. This is one. Next, CH3CH2CH2Cl. What will be the answer for this? Now, try this question, please. If it is given like this, first, write the bonds in a way you can understand. Write the bonds by separating them. After separating the bonds, start answering. Look where the more bulky group is. Look where there is more stability. Please look properly and answer. Nobody is stopping you from scoring, but you have to see it. Everyone is sitting and studying, so if you only say, "I will study for the board," and keep studying for the boards, you won't be able to score marks in NEET. Yes. So, what is the answer for this? Second one, then the first one. After that, after that, who is there? Third one? After that, the third one. After that, the fourth one. Okay? Very, very clear. Very, very, very, very clear. No doubts in this. No doubts in this. Look here. Look here. Whenever this is given, write it properly. What did I tell you? Separate and write. Look here, C-Cl, CH3, CH3, CH3. Okay? C6H5 means there is a benzene ring. Here, C6H5, CH3, CH3, CL is attached at this point. Here, CH, CH3, CH3. If you don't understand, write it down. Write it like this. Look here, if carbocation forms here, because it is nearby, it will be stabilized by resonance. Okay? That's why there is a lot of stability here. After that, he is tertiary, of course, stable. He is secondary. He is primary. Okay, done. So, next, come here. Tell me SN2. Okay, SN2 order. Okay? So, first, A, CH3Br or CH3I. Between these two, who will be more stable in SN2? I mean, more reactive? Yes, more reactive. Okay, tell A first, then B. CH3 twice CL, CH3Cl. Who is CH3I? Okay, CH3I. Why did you write CH3I? Look here, I am telling you again. Iodine is a better leaving group. Okay? It is a better leaving group. It is a super leaving group, so it will go out well. Okay? And it's a weaker base. Okay? It is also a weaker base, so it will be an easy leaving group, so it will leave easily. Next point. In the second one, in the second one, whoever has less bulkiness will be more in SN2, right? Yes, who has less bulkiness at this point? So, he has less bulkiness. So, of course, he will be more, like the last one. C, you see, CH2 double bond C-Br, Br, and C, CH2 double bond C. Very easy question. Who is it? Very, very easy question. Like, a very, very basic question. This answer is. Look here, primary, it is nearby, it will finish easily. Okay? So, next, when you come, V R K N C. I have joined our batch. Have you joined the final round? Super, ma'am. Yes, because I removed you from the main batch so that no one joins. Tell me the SN order. Okay? Okay, for one, what is the order of SN1? Higher here. First, then 2, then 3, then 4. Okay? Does anyone have any confusion about this? Where, why, in double-bonded compounds? Because many people solve these questions. Okay? But what mistake do you make? You don't even know the correct answer for all of this. You solve it without any explanation. Is it right or not? Do you people solve this without explanation? You solve it without a proper explanation, and that's why you don't understand in many places. That's why you solve it incorrectly.

Okay. Alright, next, come here. Now, you will solve by assumption. So, now you have clear clarity, like, at which point, how you will do SN1, SN2. So, if you are looking at SN1, definitely what you should look for is, is the stability of the carbocation higher somewhere? So, for that specific compound, you can give more priority. So, if you come here, you know that for SN1, for SN1, the order is tertiary, secondary, and primary alkyl halides. And for SN2, primary, secondary, and tertiary are okay. Now, just imagine you are plotting a graph for this. If you plot a graph, take SN1, SN2 here. Here, SN1. Okay? If you look closely at this graph, here, this is your zeroeth degree. Okay? This is your primary. This is your secondary. And this is your tertiary. Tertiary. Okay? Or else, just remove the zeroeth degree. I will directly teach you using secondary and tertiary. Look here. Take your primary here. Take your secondary here. And your tertiary is here. Okay? Secondary and here, your tertiary. Yes. How many of you watching this live are 7.5% students? How many of you, 7.5% students? So many of you are here? Nice. So many of you? Are all of you 7.5% 5% students? Oh my god. What is she saying? Please, why am I saying please? Why are you saying please? Okay, come here. Now, here, don't you people think that you people think that if I plot a graph for this, for SN2, my graph will start at the maximum and end here, right? Reactivity. If it is like this for SN2 here, how will it be for SN1? Starting here, going like this, and ending like this. Can everyone see the graph? Yes. Can everyone see it well? Can you people see that your graph will be somewhere like this? Okay? Look here. Here, your reactivity is maximum for primary. Here, your, here, for whom is it maximum? Tertiary is maximum. But there is a point where both SN1 and SN2 are showing reaction for secondary. Can you see? Can you see? Here, your SN1 and SN1 are showing secondary. SN2 is also showing secondary. Okay? Alright. SN1 is also showing, SN2 is also showing. What does this graph say first? If you have a primary alkyl halide, it is faster for SN1. Sorry, not SN1, SN2. Yes. SN2. If you have a secondary alkyl halide, first for SN1. Okay? See, if you have secondary, no, tertiary. If you have a tertiary alkyl halide, it is faster for SN1. So, for whom will the second one be faster? This doubt will come to everyone, right? This doubt will come to everyone, right? This doubt will come to everyone. Okay? Yes, this doubt will come to everyone. So, that's why we say, follow the conditions, follow the conditions. Yes. So, we have to look at those conditions here. Okay? So, put a brainy point. So, what will the brainy point say is, guys, if anyone has a doubt, like, I mean, if it is related to studies, ask during the break, please. We need to finish this lesson, that's why. Okay? There is still one more thing. Please, a little bit. Okay. So, see here. So, what is the brainy point? In case of a secondary halide. Yes. In case of a secondary halide. Okay? In case of a secondary halide. If you are using a strong nucleophile, will SN1 happen more, or will SN2 happen? Predominantly, will SN1 happen, or SN2? When there is a secondary halide, it will show both reactions. It will show SN1, it will show SN2. Predominantly, for whom will it be more? For SN2. If you use a weak nucleophile, if we use a weak nucleophile, it will show more SN1. Okay? Alright? No one has any doubt in this, right? Does anyone have any doubt in this? Does anyone have any doubt in this? Tell me. Okay, actually, there is a question that I make everyone solve classically every year. For now, keep this. At the end, I will put a tabular column, where we will see E1, E2, everything mixed. You will get more clarity there. Okay? Why there is confusion for many people in SN1, SN2, E1, E2, we will see that too. Okay? First, just solve this question. If I am having a compound A, and a compound B. Okay? Yes. Compound A, you have CH2Cl + O double bond O-. Okay? There is another compound, the same compound, but + O double bond O-. Okay? Alright? Here, this is your substrate. This is your substrate. This is your nucleophile. Okay? Now, what am I doing? Now, what am I doing? Here, I am taking 1 mole of this. I am taking 10 moles of this. Okay? Yes. I am taking 10 moles of this. Here, I am taking 2 moles of this. I am taking 15 moles of this. Okay? Alright? Taking 15 moles. Or, let's do it this way. Wait. I am taking two moles of this. I am taking 10 moles of this. Okay? Yes. I am taking one mole, one mole, and 5 moles. Okay? Yes. Between these two, who will show more SN1 reaction? SN1 reaction. Who will show more SN1 reaction? Unique girl, wait, ma'am, I am coming, I am coming, wait, wait. A or B? Of course, it is A. Okay? Of course, it will be A. The answer is A. Why A? Here, the SN1 reaction depends only on whose concentration? Yes. On whose concentration does it depend? Tell me quickly. It depends only on the concentration of your substrate. Okay? Another question. Here, I have removed this 2 and if I had given 1 mole here and 1 mole here, who will be more? If I remove this 2 and give 1 mole here and 1 mole here, both will react equally. Its concentration will not depend. The rate depends only on whom? SN1 rate depends only on the concentration of RX. Okay? Next, another question. I have definitely given this to all of you in the notes. What are you going to do now? You are going to put it in the comment section. Which is a strong nucleophile? Which is a weak nucleophile? Tell me the examples I gave you. Quickly, quickly, quickly, tell me. What examples did I give you people for strong nucleophile and weak nucleophile? Quickly, tell me. This is finished. Do I still need to finish only E1, E2? This is finished. Okay. Quickly, tell me. Brainy point, what are you people doing? What are you people doing? Seriously? Yes. Here, strong nucleophile and then weak nucleophile. Weak nucleophile. Okay? What comes under strong nucleophile? Your CH3O-, CH3O-. Next, alcoholic KOH, if OH- is given, that too. Next, NH2. Okay? After that, tertiary butoxide. Okay? Tertiary butoxide. All these will produce strong nucleophiles. Next, next. In your weak nucleophile, H2O, ROH, POH. Here, someone asked in the comment section, why ethanol was given and ethanol was taken in a large amount, and SN1 came. If you use ethanol here, ethanol will give a weak nucleophile. So, if you use a weak nucleophile in excess, what will you get? If you predominantly use a weak nucleophile, even though the concentration of the nucleophile does not depend on SN1, but there is a condition that you must use a weak nucleophile. Isn't that correct? Yes. So, if you use a weak nucleophile, what will happen there? What will happen there? Definitely SN1 will happen. Why will SN2 happen? Very simple. Yes. Definitely, I think everyone understood. Aishwarya, thank you, ma'am. Thank you, ma'am. Thank you, ma'am. Yes. So, if everyone understood this, tell me, we can move on. Can we move on? Yes. Can we move on? Okay. Finally, there is one box. In this one box, I will explain E1 and E2 together. Okay? Yes. Just one tabular column. In this tabular column, I will explain E1, E2 to you all. So, come here. Is only the class enough for you? If you want, read NCERT once. Just look at the example questions in NCERT. Don't look at anything else. You have understood the concept. You have seen isomerism, because the isomerism topic will be a bit mixed here. Optical isomerism, all that is okay. Stereoisomerism is mixed in this lesson. So, if you have studied isomerism, then you can sit and just look at the questions in it. How I am, the link is in the description below your course. Join, ma'am. Okay. So, if you come here, I will teach you polyhalogen compounds at the end. I will give you that in short notes today. Don't worry. When will the chemistry portion be completed? Mostly this month, I will try to complete everything by the 23rd. Okay? Now, think differently. Within Monday, I will try to complete. Up to current electricity. Now, if current electricity is finished, then the whole of the next week will be for you. Another thing is, when is the date? Where is it? I am getting leave. Okay? When is the leave coming? I have leave from the 15th or 18th. I have leave on the 18th, 19th, 20th, 21st. Leave. Okay? Because I have four days of leave, I will take classes non-stop for those four days. So, if I take classes for four days, what will happen? We can finish it easily. For all four days, I will take classes non-stop, and I will finish most of the chapters in your physics. Okay? Wave, wave optics, ray optics, and then your modern physics, everything. Okay? Everything will be finished. Don't worry. Question solving is already going on. Yes. Krishna, solve questions on one side. Why? Even if you solve in the evening, how many people watch that question solving session sitting in the morning the next day? Because we have given the whole morning time for free, right? We have given the whole morning for free, right? So, you should sit and watch the next day morning. Shakti, wait, wait, I am finishing. I am finishing. Wait. Only one more chapter needs to be finished in the batch. Only ray optics needs to be finished. I will finish this by the 23rd, and then in the batch, I will finish that ray optics. Or else, if I take a space in between, I am thinking of packing everything up and teaching only the remaining part of that chapter there. Let me, let me think. Okay? Yes. You don't have any problem, right? After finishing the final round, if I take two or three days, I think I will finish it in the batch. Only ray optics, only ray optics is left. Yes. That's what I am thinking. Okay? No problem. Okay. Done. Alright. Because it is very hectic. Otherwise, I would have taught this sometime. You know yourself. If I had skipped classes due to personal reasons like hecticness, like many people here are saying, uncle's wedding, brother's wedding, due to personal reasons, and said it was hectic, okay? But because I am taking classes here and also taking classes here, that's why I am unable to finish this. Many people here skip classes for personal reasons and run away. They say, "The result will speak," even if the syllabus is not completed. I don't understand what they are saying. They say, "The result will speak," even if the syllabus is not completed. Hey, finish the syllabus first. Only after finishing the syllabus, the result will speak. What is happening here? It's like that when I see them. So, come here. Write E1 and E2 here. Okay? Yes. E1 and E2. Just one box, everything will be finished. Here. Look. In E1, E2, the same, just like it was in SN1, two steps. Here, one step. It's the same. Okay? So, the first thing here is, drink water. Your dear is telling you. Oh my god. What am I supposed to say? I have nothing to say. I am innocent. Your physics lecturer, similar to DC Pandey's book, did you see it or not? Ritika Shree. Okay. So, come here. In E1, E2, there is only one difference. Look here. In E1, like it had double steps in SN1, this is a two-step reaction. Two-step reaction. Okay? Two-step reaction. This is a single-step reaction. Okay? Alright? This is a single-step reaction. Because it is a two-step reaction, whatever things you saw in SN1 will happen here. Carbocation formation will happen. Rate is directly proportional to RX. Okay? Rate is directly proportional to RX. Here, the rate is directly proportional to RX and nucleophile. Both of these will happen similarly here. Okay? But there is only one difference. Only one difference. Look here. If you look at the order, this is first order. The order here is second order. Second order. But reactivity, if you look at the nucleophile, reactivity, nucleophile. Here, you should use a weak nucleophile. Nucleophile. Here, you should use a strong one. Okay? Should use strong. Reactivity. Reactivity. Tertiary, tertiary, tertiary, secondary, and primary. Here too, reactivity is tertiary, secondary, and primary. So, now, what question am I asking? SN1 and weak. SN, E1 is also weak. Okay? Here, if you look at the reactivity, for him, tertiary, secondary, primary. For him too, tertiary, secondary, primary. So, how will you differentiate between E1 and SN1? Tell me. Ma'am, initially, I haven't told you anything. Oh my god. What happened? Tell me below. Tell me. Here, how will you differentiate between him and SN1? I will tell you. SN1 happens only at low temperature. How does it happen? Only at low temperature. Less than or equal to 25 degrees Celsius. E1 happens only at high temperature. High temperature means how much? Greater than or equal to 50 degrees Celsius. Between these two temperatures, in between both temperatures. Okay? Both SN1 and E1 are seen. Okay? Both are possible. Clearly? Yes. Both are possible. Very, very, very important reactions, both of these. Now, what am I doing? I am giving a question. Just tell me what this question is. Okay? Just one question. Just one question. Okay. You tell me the answer. Which one? This is not needed. Wait. Okay. Which will undergo E2 reaction? Okay? This is the question for all of you. You don't know one thing. For the last one week, I have not attended my clinical postings. Because I sleep at 1 or 2 AM every night, and then wake up at 4:30 AM to fast, and then I can't even go to college. Sleeping for two hours, two hours. Okay? That's why I am literally going to college only in the afternoon this week. Only in the afternoon. I wake up and go to college in the afternoon. That's how I am doing it. Because I am taking classes. And also, because of the question paper preparation, it is going very hectic. Yesterday, I literally went home at 2 AM. Slept for a while. I think it became 2 AM at night. Slept. Then it became 3 AM. Woke up at 3:30 AM to fast. Then woke up again. I couldn't even go to college. I thought I would go in the morning. Then I slept soundly. I woke up at 11 AM and left for college. I reached college at 12 PM. My sleep pattern has been so disturbed. There is no sleep in my eyes. Do you know when it comes correctly? 3 AM. Only at 3 AM, my eyes don't see sleep. Until then, sleep doesn't even come. Yes? Literally, I am saying, my sleep pattern has changed so badly. I am not even feeling sleepy till 3 AM. Only after 3 AM, I feel that sleep. Take a break for 5 minutes. Charge is not there. I will give you a break after I finish writing this question. Wait. Because there is no charge. Okay. Tell me. Among these three, who will not undergo E2 reaction? Who will not undergo E2 reaction? The camera charge is not over yet. I think it is there. Let's see. Complete my syllabus by watching your lectures. What new lectures? Yah. Just look at my notes. Because a lot of new content has been added. Look and practice the questions once. There are many questions. Barbi World. Thank you, ma'am. Thank you. Thank you. Thank you. What is the answer to this question? What is the answer to this question? Right. How many people got it? Why? Why is the order 3? Sleep up to what? Final price. Is that what comes? I don't understand. How much more can be reduced for the printer test series? Why is it C? Carbon valency exceeded? Where did it exceed? It didn't exceed anywhere. Oh, are you talking about after elimination? Okay. Okay. Okay. Yes. So, after elimination, here, if elimination happens here, the bond is possible. If elimination happens here, the bond is possible. But if elimination happens here, is a bond possible here? Definitely not. So, because of that one thing, it is not possible. Next, wait, let me just finish these things. After that, go. Oh my god. Okay. Let's start. Yes. So, here, the answer is the third one. Yes. The answer is this option. Okay. So, put another box here. I will ask one more question before this. Just a minute. Just a minute. Just a minute. Okay. So, here, there is a Br. Okay? And I am giving you a condition. CH3, CH2, OH is there at 100 degrees Celsius. What reaction will this give? Will it give SN1? Will it give SN2? Will it give E1? Will it give E2? First, if you are given a question like this, what should you look at? What is given here? Primary, secondary, tertiary? What alkyl halide is here? Here, first, it is tertiary. If it is tertiary, only two things are possible. Three things are possible for tertiary. One, it should be SN1. It should be SN1. Or it should be E1. Or it should be E2. Okay? Next, here, is this polar protic or polar aprotic? Is this polar protic or polar aprotic? This is polar protic. So, if it is polar protic, is E2 possible? Is E2 possible? Question. Polar protic. Then definitely possible. So, we have eliminated him. Okay. Now, next, here. Temperature. If the temperature is high, will it show SN1 or E1? I said SN1 happens only at low temperature. So, what is possible here? Only E1 is possible. SN1 is not possible. So, what is the answer? CH3CH=CH2CH3. Clear? Just elimination will happen. Okay? Elimination has happened here. No one has any doubt in this. Now, does anyone have any doubt in this? Now, very, very clear. No doubts still now. Okay. Next, come here. Another question. Just a minute. Okay. Another question. Will a more stable product be formed in E1 or E2? Will a more stable product be formed in E1 or E2? Why is it formed in E1? Why is it formed in E1? Because in E1, what formation will happen? Carbocation formation will happen. In E2, carbocation formation will not happen. Okay? Yes. Alright. For example, another question here. Look at this question. CH3 C(CH3)3 CH3 CH Cl CH3. There are two reactions here. One and two. Okay? There is CH3 C(CH3)3 CH3 and CH3 C=CH2 CH3 and PH3 has been formed. Okay? Okay. Done. So, here, one and two. Between these two, why between these two? Oh, shoot. Wait a minute. I have put one extra carbon. So, add one extra carbon here. Okay? Yes. Now, between these two, between these two, tell me which is E1 and which is E2. Yes. Tell me. Which is E1? Which is E2? Tell me. Done. Yes. Tell me which is E1 and which is E2. Very simple question. Very simple question. I will even explain the mechanism. Wait. See here. This would have been your E1, and this would have been your E2. Because E2 is a single-step reaction. So, being a single-step reaction, as soon as this Cl left, your double bond would have formed here. That's all. The reaction is finished. Now, what would have happened in D1? This would have left. Carbocation formation would have happened. Because this methyl group migrated here, this methyl group rearranged. After that, what would have formed here? A double bond would have formed after an H left. Correct? So, did everyone understand the difference in how E1 and E2 reactions happen? If everyone understood that difference here, tell me. We can move on to the last tabular column. Because from this main tabular column, you will learn what you are going to study is how all your E1, E2 create differences. Okay? And there is a special point here. If, if in the solvent, if tertiary butoxide, what is this called? Tertiary butoxide is given as a nucleophile, then the Hoffman product will become major. Okay? Alright? So, the Hoffman product will become major. Note this point. Next, let's go to our tabular column. This tabular column is a very important tabular column. Please, everyone note this down. It will be very, very, very helpful. Sir, is E2 anti-elimination? Yes, sir. Yes, sir. Yes, sir. E2 does anti-elimination. Yes. In E2, CH3 comes above, right? Did I put it less? What? One, two. Did you see or not? Thank you. Okay. Alright? Okay. Come here. Here, mechanism, solvent, then temperature, then nucleophile. Okay? Alright? Here, for primary, what mechanism is possible? Only SN2 is possible. Nothing else is possible except SN2. Okay? Solvent should be polar aprotic solvent. Polar aprotic solvent. Temperature should be low temperature. For SN2, nucleophile should be a strong nucleophile. Next, come here. If there is secondary, then for secondary, a total of four things are possible. One, SN1 is possible. Another, E1 is possible. Another, SN2 is possible. E1 is possible. SN2 is possible. And E2 is also possible. Okay? Now, if it is SN1, here, it should be a polar protic solvent. Low temperature. Okay? For SN1 to happen in secondary, and there should be a weak nucleophile. Correct? If E1 happens, it should be polar protic. High temperature. And here too, weak nucleophile. Okay? Next, if SN2 happens, it should be polar aprotic solvent. Low temperature. And there should be a strong nucleophile. Okay? If E2 happens, it should be polar aprotic solvent. High temperature. And there should be a strong nucleophile. Now, do you understand what to use where? Definitely, this, in this single tabular column, you will get clarity on many things. Because I have written everything clearly here. Next, if you look here, tertiary. So, for tertiary, three things are possible. One, SN1. Another, E1. Another, E2. For SN2, it should be a polar protic solvent. Low temperature. Weak nucleophile. For this, it should be polar protic. High temperature. And weak nucleophile. For this, it should be polar aprotic. Polar aprotic. For him, high temperature. Elimination always happens at high temperature. Okay? Yes. Strong nucleophile should be there. So, that's it. This part is finished. Wait. After this, there are still some chapters to finish. Don't move, just sit. Okay? Alright. Have all of you written this? Have all of you written this? Write it down. This is very, very, very important. Tell me when you have finished writing this. We can move on to our next reaction. We can move on to reaction with metal. Reaction with metal. I have already taught maximum of everything. So, I am not going to teach it again. Okay? Shall I give a question? One question. One question. Come. I will give you a question. Show me the solution. Yes. So, wait a minute. There is one thing I don't understand. You are asking about completing the syllabus, completing the syllabus. I am teaching all this for revision. You are sitting and studying fresh. You are sitting and studying fresh now. Honestly, I don't understand. Why are you coming just to bother me? I am also watching. They are coming just to bother me. Oh, okay. Wait a minute. There are still some reactions. I will finish these. Then I will give the question. Okay? Reaction with metals. Reaction with metals. First, Wurtz reactions. Reaction, refer to hydrocarbons. Second, Frankland reaction. Refer to hydrocarbons. Okay? Next, if you come, Friedel-Crafts reaction. Friedel-Crafts reaction will happen. I will tell you. There will be a benzene ring. In this benzene ring, we will be treating an alkyl halide in the presence of anhydrous AlCl3. Okay? What formation will happen here is, an electrophile formation will happen. CH3+ in case it is a large branch, this electrophile formation will involve the shift of this carbocation, rearrangement, and then it will attack. Remember. Okay? So, if you don't do that, the answer will be wrong. I will tell you again. So, if you attack this directly, you will get the answer. Okay? Next, next, if you come, Grignard reagent reaction. Grignard reagent. So, Grignard reagent, refer to hydrocarbons. Refer to hydrocarbons. Next, reaction of.

Reaction of dihalides refer hydrocarbons. Next, next, reaction with KCN. Reaction with KCN. I will teach this, don't worry, okay? Look here. CH2, CH2, CH2, CH2, Cl, and Cl, okay? And Cl. In the presence of, in the presence of KCN, if you treat this, what happens is a nucleophilic substitution reaction will occur. Okay? A nucleophilic substitution. This CN will go and replace the Cl at this position. CH2, okay? CH2, CH2, here one CN, here one CN. But this reaction will not stop here. You will further treat this with H2O. CN has three bonds. If you break all three bonds and do hydrolysis, you will get an acid here, correct or not? So, here one CH2, here one CH2, COOH, COOH. Nitrogen will become NH3 and go out. Okay? NH3 will go out. Next, in case in this same question, if it is not Cl like this, but CH3, CH, Cl, Cl, like this, then what will happen, listen. So, if you react this with KCN, both your CNs will go and attach to the same carbon geminally. Here one CN, here one CN. Now, after finally reacting with H2O, after reacting with H2O, what will happen? Yes, on the same carbon, there will be two COOH groups. Okay? Two COOH groups on the same carbon. Stable or unstable? Of course, unstable. So, since both are on the same one, you need to remove one CO2 from this. So, by removing, you can only keep one acid. CH2, COOH. 2 moles of energy, yes. It's 2 moles. I haven't balanced the moles here. Okay, done. So, these two reactions are again expected in NEET 2026. Okay? This question is expected in NEET 2026. I'm telling you again. So, you might get a question from this. Make sure you study it properly. Next, coming to the Unstaker reaction. So, in the Hunsdiecker reaction, you need to take a silver salt. A silver salt, yes. Take a silver salt and in the presence of some halogen and CCl4, if you react it with CCl4, you will get an alkyl halide. CX2, by AX will be obtained. Okay? This reaction is a very, very, very, very, very important naming reaction. This is also a reaction that is possible in NEET 2026. Okay? Next, coming to aryl halides. Okay. Aryl. Aryl. Come here. We will finish everything. Come. Yes. Aryl halides. So, if you look at aryl halides, the general methods of preparation for aryl halides. You would have studied this in the chemical reactions of, in the chemical reactions of aromatic hydrocarbons. Okay? General preparation. General preparation. Now, if you look at it, take a benzene ring. Plus, not plus, but in the presence of AlCl3, if you treat it with Cl2, it will give out AlCl4- + Cl+. Take this and do electrophilic substitution reaction. The answer will be Cl. Okay? Next, take a benzene here. Okay? Not benzene, but a phenol. So, take phenol and treat it with PCl5. What will this do? It will directly attack the OH, push it out, say "get out!" and throw it away, and give Cl here. PCl3, HCl will come. Next, after that, we have another thing. What do we have? A special item. Here, we will take benzene diazonium chloride. Okay? This benzene diazonium chloride, Cl-. Okay? If you treat this benzene diazonium chloride in the presence of Cu and HCl, what will you get? Directly, only Cl will remain. The remaining N2 gas will fly away. What is the name of this reaction? Gattermann reaction. What is it? Gattermann reaction. Okay. Gattermann reaction. Here, instead of Cu, you can use Cu powder. Okay? Okay. This is Gattermann reaction. Next, instead of this, you can use another compound. Sometimes, Cu powder and HCl can also be used. Next, coming to your, if you want iodine in this same reaction, N2+ Cl-. In the presence of KI. Okay? KI. Do you know this was a question asked in NEET 2025? A question asked in NEET 2025. Go and check. Plus N2 gas. Plus KCl. Next, why? Next, coming to your, if I want iodine, sir, if I want fluorine, sir, then N2Cl. Yes, yes. If I want fluorine, sir, then okay? Here, we will use HBF4. Just like there is Swarts reaction for fluorine, here, what reaction is this? What is the name of this reaction? This reaction is called Balz-Schiemann reaction. Okay. Balz-Schiemann reaction. Okay. Balz-Schiemann reaction. Next, we are going to look at the chemical reactions of aryl halides. Wait for just one second, guys. Just one second. Oh, did you not go? Are you not asleep yet? Are you not asleep? Go to sleep. It's late. Okay, okay. Okay. Okay. So, come here. Chemical reactions of aryl halides. Okay. There are three things in chemical reactions. Yes. So, in chemical reactions, chemical reactions of aryl halides. Okay. In this, a total of three things will come to you. Again, one is nucleophilic substitution, another is electrophilic substitution, and another is your reaction with metals. Monish, how did you find out so quickly? How did you find out so quickly what I am going to do? How, Monish? Okay. So, nucleophilic substitution reaction. Electrophilic substitution, and reaction with metals. Okay. In this, first, nucleophilic substitution. Okay. So, in nucleophilic substitution, just tell me. Here, there is Cl. Is this Cl an ordinary Cl or a Cl with extraordinary power? Do you think the bond between this Cl and this benzene is an ordinary bond? Or do you think it is an extraordinary bond? Do you think you can break this easily? Yes, tell me. Do you think you can break this easily? Definitely. Riya, yes. Anna, Annie, want to come? Come. Oh, someone. Why is he like this? Okay, okay, okay, okay, okay, okay, okay. Sorry, sorry. C, H, Cl. I don't have interest in love, so L means I don't want L. So, I'm okay. No, no, no, no, no. I don't agree to anything. No, I don't agree to anything. No, no, no, no, no. No. No, no, no, no. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. No. 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